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4 years ago

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A driver in a car traveling at a speed of 21.8 m/s sees a cat 101m away on the road. How long will it take for the car to accele

rate uniformly for 3.2 km in 3.5 min. How fast (in m/s) is the car moving after this time?

1 answer:

Ket [755]4 years ago

8 0

The answer would be 9.1 s

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An Olympic runner competing in a long-distance event finishes with a time of 2 hours , 15 minutes , and 23 seconds . The event h

Talja [164]

Answer:

The average speed of the runner is 18.2 km/h.

Explanation:

Hi there!

The average speed is calculated as the traveled distance over time:

speed = traveled distance / elapsed time to cover that distance

We have to find the speed in km/h, so let´s start converting the time into hours:

23 s · (1 min/60 s) = 0.38 min

15.38 min · (1 h / 60 min) = 0.26 h

Total time: 0.26 h + 2 h = 2.26 h

The distance traveled in km is:

25.5 mi · (1.61 km/ 1 mi) = 41.1 km

Then, the average speed will be:

speed = 41.1 km / 2.26 h = 18.2 km/h

The average speed of the runner is 18.2 km/h.

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3 years ago

Identify the part of a carrot plant that contains chlorophyll and the part that contains

Alex Ar [27]

Answer:

Leaves and Roots

Explanation:

The leaves of carrots contain chlorophyll which gives them their green color.

Stored in the carrot roots is extra glucose that serves as a food source for the second year's growth of the carrot plant. The carrot plant needs this stored eneergy to reproduce in its second year.

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3 years ago

What percentage of Earth is covered with water?<br><br> 97<br> 70<br> 3<br> 3.5<br> 20<br> 69

Leni [432]

Answer:

70 percent

Explanation:

the answer is 70 percent

7 0

3 years ago

Read 2 more answers

Dennis throws a volleyball up in the air. It reaches its maximum height 1.1\, \text s1.1s1, point, 1, start text, s, end text la

rewona [7]

Answer:

If max height = 1.1 meters, then initial velocity is 3.28 m/s

If max height is 1.1 feet, then the initial velocity is 5.93 ft/s

Explanation:

Recall the formulas for vertical motion under the acceleration of gravity;

for the vertical velocity of the object we have

$v=v_0-g \,t$

for the object's vertical displacement we have

$y-y_0=v_0\,t - \frac{g}{2} \,t^2$

If the maximum height reached by the object is given in meters, we use the value for g in $m/s^2$ which is: $9.8\,\,m/s^2$

If the maximum height of the object is given in feet, we use the value for g in $ft/s^2$ which is : $32\,\,ft/s^2$

Now, when the ball reaches its maximum height, the ball's velocity is zero, so that allows us to solve for the time (t) the process of reaching the max height takes:

$v=v_0-g \,t\\0=v_0-g \,t\\g\,\,t=v_0\\t=\frac{v_0}{g}$

and now we use this to express the maximum height in the second equation we typed:

$y-y_0=v_0\,t - \frac{g}{2} \,t^2\\max\,height=v_0\,(\frac{v_0}{g}) - \frac{g}{2} \,(\frac{v_0}{g})^2\\max\,height= \frac{v_0^2}{2\,g}$

Then if the max height is 1.1 meters, we use the following formula to solve for $v_0$ :

$1.1= \frac{v_0^2}{2\,9.8}\\(9.8)\,(1.1)=v_0^2\\v_0=10.78\\v_0=\sqrt{10.78} \\v_0=3.28\,\,m/s$

If the max height is 1.1 feet, we use the following formula to solve for $v_0$ :

$1.1= \frac{v_0^2}{2\,32}\\(32)\,(1.1)=v_0^2\\v_0=35.2\\v_0=\sqrt{35.2} \\v_0=5.93\,\,ft/s$

5 0

3 years ago

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Burning coal produces which type of gas?

Aleksandr [31]

Answer:

carbon dioxide

Explanation:

In addition to carbon dioxide, discussed below, coal plants all produce the following pollutants: Sulfur dioxide, which leads to acid rain. Coal combustion is the leading source of US sulfur dioxide emissions. Nitrogen oxides, key contributors to ground-level ozone (smog) and respiratory illnesses.

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4 years ago

Read 2 more answers