Suppose you take a short piece of wire that is not attached to anything and move it up and down in a magnetic field. Explain whe
2 answers:
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Answer:
The magnetic field strength inside the solenoid is .
Explanation:
Given that,
Radius = 2.0 mm
Length = 5.0 cm
Current = 2.0 A
Number of turns = 100
(a). We need to calculate the magnetic field strength inside the solenoid
Using formula of the magnetic field strength
Using Ampere's Law
Where, N = Number of turns
I = current
l = length
Put the value into the formula
(b). We draw the diagram
Hence, The magnetic field strength inside the solenoid is .
