The mass of the piece of lead is calculated using the below formula
Q(heat)= mC delta T
Q = 78.0 j
M=mass =?
C=specific heat capacity ( 0.130 j/g/c
delat T=change in temperature = 9.0 c
by making M the subject of the formula
M = Q/ c delta T
M= 78.0 j/ 0.130 j/g/c x 9.0 c = 66.7 g of lead
Following are the Balanced Reactions,
Reaction 1:
(NH₄)₂CO₃ → <u>2</u> NH₄⁺ + CO3⁻²
Reaction 2:
PbI₂ → Pb⁺²<span> + <u>2</u> I</span>⁻¹
Reaction 3:
<span>(NH</span>₂<span>)</span>₃<span>PO</span>₄ → <span><u>3</u> NH</span>₄⁺ <span>+ PO</span>₄⁻³
Answer:
3
Explanation:
third answer might be right
