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posledela
3 years ago
7

The _____ rate is the number of particles that react in a given time to form products.

Chemistry
2 answers:
Elenna [48]3 years ago
6 0
B. reaction rate is the answer
IgorLugansk [536]3 years ago
6 0
The correct ANWSER is b Mark me the brainliest anwser
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What name is given to the minimum amount of energy needed by particles for them to react when they collide?
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Activation

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Los pulmones y el aparato respiratorio nos permiten respirar. Permiten la entrada de oxígeno en nuestros cuerpos (inspiración o inhalación) y expulsan el dióxido de carbono (expiración o exhalación). Este intercambio de oxígeno y dióxido de carbono recibe el nombre de "respiración"

La función del aparato respiratorio es mover dos gases: <em>el oxígeno y el dióxido de carbono</em>

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What happens when sodium and chlorine react to make table salt <br><br> Please help
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Which of the following is an example of the characteristic of movement?
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5 0
3 years ago
I want to know the steps.
Artyom0805 [142]

The answer for the following problem is described below.

<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>

Explanation:

Given:

enthalpy of combustion of glucose(ΔH_{f} of C_{6}H_{12} O_{6}) =-1275.0

enthalpy of combustion of oxygen(ΔH_{f} of O_{2}) = zero

enthalpy of combustion of carbon dioxide(ΔH_{f} of CO_{2}) = -393.5

enthalpy of combustion of water(ΔH_{f} of H_{2} O) = -285.8

To solve :

standard enthalpy of combustion

We know;

ΔH_{f}  = ∈ΔH_{f} (products) - ∈ΔH_{f} (reactants)

C_{6}H_{12} O_{6} (s) +6 O_{2}(g) → 6 CO_{2} (g)+ 6 H_{2} O(l)

ΔH_{f} = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]

ΔH_{f} = [6 (-393.5) + 6(-285.8)] - [0 - 1275]

ΔH_{f} = 6 (-393.5) + 6(-285.8)  - 0 + 1275

ΔH_{f} = -2361 - 1714 - 0 + 1275

ΔH_{f} =-2800 kJ

<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>

7 0
3 years ago
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