1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vladimir [108]
3 years ago
5

Fill in the blanks using terms from this unit.

Chemistry
2 answers:
jarptica [38.1K]3 years ago
7 0

Answer:

Even though plants are rooted in the ground, they still move, exert force, and do work.

Plant cells have very strong cell walls that allow pressure to build up inside of the cell as water is absorbed. This pressure is called turgor.

When turgor pressure is high enough in a cell, the cell walls become firm and as a result, the cell becomes rigid and the plant is able to stand tall and straight.

When a plant does not get enough water, the turgor pressure inside of the cells decreases. A decrease in pressure pushing against the cell wall causes the cells to lose their shape and shrink. This causes the plant to begin to droop or wilt.

When the wilted plant gets enough water, the cells will become rigid again, and the plant will stand firm and straight once again.

Explanation:

kolbaska11 [484]3 years ago
5 0

Answer:

See the answer below

Explanation:

Even though plants are rooted in the ground, they still move, exert <u>force,</u> and do<u> work</u>.

Plant cells have very strong cell walls that allow <u>pressure</u> to build up inside of the cell as water is absorbed. This pressure is called <u>turgor</u>.

When turgor pressure is high enough in a cell, the cell walls become <u>firm</u> and as a result, the cell becomes rigid and the plant is able to stand <u>tall</u> and<u> straight</u>.

When a plant does not get enough water, the turgor pressure inside of the cells <u>decreases.</u> A decrease in <u>pressure</u> pushing against the cell wall causes the cells to lose their <u>shape</u> and <u>shrink</u>. This causes the plant to begin to droop or <u>wilt</u>.

When the wilted plant gets enough water, the cells will become rigid again, and the plant will stand firm and straight once again.

You might be interested in
A compound is 150.86 g carbon, 8.86 g hydrogen, and 20.10 g oxygen by
Ivahew [28]

Answer:

C20 H14 O2

Explanation:

Remark

This is a sample, which the question does not say and should. It is a fraction of 1 mole. So what you have to do is multiply the numbers given by x and equate it to 286.28

Equation

150,86* x + 8.86*x + 20.1*x  = 286.28

179.8x = 286.28

x = 286.26/179.8

x = 1.592

Now multiply the given numbers by 1.592

150.86 * 1.592 = 240.58

8.85 * 1.592 = 14.1

20.1 * 1.592 = 32

Rounding you get

240/12 = 20

14.1/1 = 14

32/16 = 2

C20 H14 O2

8 0
3 years ago
The Haber process for making ammonia can be described by the balanced equation,
Natasha_Volkova [10]

Answer:

coverwow customer care number 8388026087//8388026087

3 0
3 years ago
Convert to moles: show work
Ket [755]
I’m just letting you know this is really easy you just calculate the molar mass of each compound and divide the amount of the compound (grams) by the molecular Mass
6 0
3 years ago
At 1000°C, cyclobutane (C4H8) decomposes in a first-order reaction, with the very high rate constant of 79 1/s, to two molecules
leva [86]

Explanation:

It is known that for first order reaction, the equation is as follows.

           t = \frac{2.303}{K} log \frac{[C_{4}H_{8}]_{o}}{[C_{4}H_{8}]_{t}}

    t = ?,        K = rate constant = 79 1/s

Initial conc. of C_{4}H_{8} = 1.68

Decompose amount of C_{4}H_{8} = 52% of 1.68

                                                   = \frac{52}{100} \times 1.68

                                                   = 0.8736

                                                   = 0.87

Now, [C_{4}H_{8}]_{t} = (1.68 - 0.87)

                         = 0.81

Therefore, calculate the value of t as follows.

               t = \frac{2.303}{K} log \frac{[C_{4}H_{8}]_{o}}{[C_{4}H_{8}]_{t}}

                  = \frac{2.303}{79 s^{-1}} log \frac{1.68}{0.81}

                  = \frac{2.303}{79 s^{-1}} \times 0.316

                  = 9.212 \times 10^{-3} s

                  = 0.00921 s

Thus, we can conclude that 0.00921 s will be taken for 52% of the cyclobutane to decompose.

7 0
3 years ago
How do I do this I need help?!
VARVARA [1.3K]
Https://www.musical.ly/v/MzU0MzExMjk0NjM2ODgwODM3NTA5MTI.html
8 0
3 years ago
Other questions:
  • An ionic bond is a bond between ____.
    9·2 answers
  • What value was a mole originally based upon?
    13·1 answer
  • A gas-filled balloon having a volume of 3.50 L at 1.20 atm and 18°C is allowed to rise to the stratosphere (about 30 km above th
    11·1 answer
  • Write a balanced equation for the reaction that occurs in each of the following cases: (a) Potassium metal is exposed to an atmo
    15·1 answer
  • Which color has a higher frequency, <br> A.red light<br> B.blue light
    11·1 answer
  • I NEED HELP PLEASE, THANKS!
    9·1 answer
  • What type of energy warms earths surface?
    10·1 answer
  • Refers to the distance from one wave peak to the next wave peak. (Lesson
    9·2 answers
  • 1. Write the chemical formula for slacked lime
    13·1 answer
  • How many significant figures are in the following number?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!