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Paladinen [302]
3 years ago
5

Total water content in the earth remains constant. comment upon the following​

Chemistry
2 answers:
iren [92.7K]3 years ago
8 0

Answer:

the water is constant

:(

Explanation:

NARA [144]3 years ago
4 0

Answer:

The total water content in the earth remains nearly constant.

Explanation:

  • The amount of water on earth is nearly same as the amount of water that was on earth in Mesozoic era.
  • Plants and animals use water as a raw material in their growth, but that water is eventually returned to earth.
  • When the UV light breaks the water molecules in higher atmosphere, some water is lost.But it is compensated by the water that enters the earth through meteors and comets.
  • The water content is not constant but through the series of biochemical reactions,the water level is nearly the same.

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CO2 + H2O -------> H2CO3 balance and classify this equation
borishaifa [10]
CO2 + H2O = H2CO3
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Your equation is already balanced, and the reaction type is: </span><em><u>synthesis.</u></em>
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4 years ago
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The half-life of bismuth-210, 210bi, is 5 days. (a) if a sample has a mass of 184 mg, find the amount remaining after 15 days.
ASHA 777 [7]

Answer:- 23.0 mg

Solution:- Radioactive decay obeys first order kinetics and the first order kinetics equation is:

lnN=-kt+lnN_0

where, N_0 is the initial amount of radioactive substance and N is it's amount after time t. k is the decay constant.

From given information, Original amount, N_0 of the radioactive substance is 184 mg and we are asked to calculate the amount N after 15 days. It means, t = 15 days

Half life is given as 5 days. From the half life, we could calculate the decay constant k using the equation:

k=\frac{0.693}{t_1_/_2}

where, t_1_/_2 is the symbol for half life. let's plug in the value of half like to calculate k:

k=\frac{0.693}{5days}

k=0.1386day^-^1

Let's plug in the values in the first order kinetics equation and solve it for N:

lnN=-0.1386day^-^1(15days)+ln184mg

lnN=-2.079+5.215

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N=e^3^.^1^3^6

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3 0
4 years ago
At 22 °C, an excess amount of a generic metal hydroxide, M(OH)2, is mixed with pure water. The resulting equilibrium solution ha
brilliants [131]

Answer:

2.29x10⁻¹² is Ksp of the salt

Explanation:

The Ksp of the metal hydroxide is:

M(OH)₂(s) ⇄ M²⁺ + 2OH⁻

Ksp = [M²⁺] [OH⁻]²

As you can see in the reaction, 2 moles of OH⁻ are produced per mole of M²⁺. It is possible to find [OH⁻] with pH, thus:

pOH = 14- pH

pOH = 14 - 10.22

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pOH = -log[OH⁻]

<em>1.66x10⁻⁴ = [OH⁻]</em>

And [M²⁺] is the half of [OH⁻], <em>[M²⁺] = 8.30x10⁻⁵</em>

<em />

Replacing in Ksp formula:

Ksp = [8.30x10⁻⁵] [1.66x10⁻⁴]²

Ksp = 2.29x10⁻¹² is Ksp of the salt

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