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nikitadnepr [17]
3 years ago
5

Which of the following processes have a ΔS > 0? A. N2(g) + 3 H2(g) → 2 NH3(g) B. Na2CO3(s) + H2O(g) + CO2(g) → 2 NaHCO3(s) C.

CH3OH(l) → CH3OH(s) D. All of these processes have a ΔS > 0. E. CH4(g) + H2O (g) → CO(g) + 3 H2(g)
Chemistry
1 answer:
Olegator [25]3 years ago
4 0

Answer:

ΔS > 0 only for choice E: CH4(g) + H2O (g) → CO(g) + 3 H2(g)

Explanation:

Our strategy in this question is to use the trend in entropies :

S (solids)  less than S (liquids) less than S (gases)

Also we have to look for the  molar quanties involved of each state and their change to answer the question:

A. N2(g) + 3 H2(g) → 2 NH3(g)

Here we have 4 moles gases going to 2 moles of products, so the change in entropy is negative.

B. Na2CO3(s) + H2O(g) + CO2(g) → 2 NaHCO3(s)

The change in entropy is negative since we have 2 mol gases in the reactants and zero in the products.

C. CH3OH(l) → CH3OH(s)

A liquid has a higher entropy than a solid so ΔS is negative

D. False see A,B,C

E. The change in moles of gases is 4 - 2= 2, therefore  ΔS is greater than O.

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When the amount of heat gained = the amount of heat loss

so, M*C*ΔTloses = M*C* ΔT gained

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4 0
3 years ago
When the equation below is balanced with the smallest possible integer coefficients, what is the coefficient for PH3?
Vikki [24]

Answer:

The coefficient for PH3 is 8. Option D is correct.

Explanation:

Step 1: The unbalanced equation

P2H4(g) ⇆ PH3(g) + P4(s)

Step 2: Balancing the equation

P2H4(g) ⇆ PH3(g) + P4(s)

On the left side we have 4x H (in P2H4), on the right side we have 3x H (in PH3). To balance the amount of H on both sides, we have to multiply P2H4 on the left side by 3 and PH3 on the right by 4.

3P2H4(g ) ⇆ 4PH3(g) + P4(s)

On the left side we have 6x P (in 3P2H4) on the right side we have 8x P (4x in 4PH3 and 4x in P4). To balance the amount of P on bot hsides, we have to multiply 3P2H4 by 2 and 4PH3 also by 2. Now the equation is balanced

6P2H4(g ) ⇆ 8PH3(g) + P4(s)

The coefficient for PH3 is 8. Option D is correct.

5 0
4 years ago
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