Answer:
Mass released = 8.6 g
Explanation:
Given data:
Initial number of moles nitrogen= 0.950 mol
Initial volume = 25.5 L
Final mass of nitrogen released = ?
Final volume = 17.3 L
Solution:
Formula:
V₁/n₁ = V₂/n₂
25.5 L / 0.950 mol = 17.3 L/n₂
n₂ = 17.3 L× 0.950 mol/25.5 L
n₂ = 16.435 L.mol /25.5 L
n₂ = 0.644 mol
Initial mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.950 mol × 28 g/mol
Mass = 26.6 g
Final mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.644 mol × 28 g/mol
Mass = 18.0 g
Mass released = initial mass - final mass
Mass released = 26.6 g - 18.0 g
Mass released = 8.6 g
Answer:
(a). 4
(b). 1 triple bond.
(c). 1
(d). 1 ring.
Explanation:
Without mincing words let's get started. So, we have that the chemical formula for the compound is C8H10. So, we are given from the question that lindlar's catalysts which is represented by H2 / Pd / CaCO3 and used in hydrogenation especially from alkyne to alkene.
(a). The degrees of unsaturation in the unknown can be calculated as;
[ (2 × Number of carbon atoms) + (2 ) - (number of Nitrogen atoms) - (number of hydrogen atoms) - number of halogens) ÷ 2
= [(2 × 8) + 2 - 0 - 10 - 0 ] ÷ 2.
=( 16 + 2 -10 ) ÷ 2.
= ( 18 - 10) ÷ 2 = 8/2 = 4.
(b). The number of triple bonds is 1 because we are given from the question that "On catalytic hydrogenation over the Lindlar catalyst, 1 equivalent of hydrogen is absorbed" and this is the work of the catalyst to prevent the alkyne from going to alkane straight.
(c). The number of double bonds is 1 because we are given from the question that "On hydrogenation over a palladium catalyst, 3 equivalents of H2 are absorbed".
(d)The number of rings is 1
Answer:
wavelength = wave velocity/frequency.
Explanation:
c
is a constant. It is usually given as
3.00
×
10
8
m/s or
3.00
×
10
10
cm/s rounded to three significant figures.
Wavelength is measured in meters, centimeters, nanometers, etc...).
Frequency has a unit of
1/s
which means
1
cycle per second. It is also given the unit Hertz (Hz) in honor of German physicist Heinrich Hertz who proved the existence of electromagnetic waves.
1
Hz
=
1/s
.
Numa máquina térmica uma parte da energia térmica fornecida ao sistema(Q1) é transformada em trabalho mecânico (τ) e o restante (Q2) é dissipado, perdido para o ambiente.
sendo:
τ: trabalho realizado (J) [Joule]
Q1: energia fornecida (J)
Q2: energia dissipada (J)
temos: τ = Q1 - Q2
O rendimento (η) é a razão do trabalho realizado pela energia fornecida:
η= τ/Q1
Exercícior resolvido:
Uma máquina térmica cíclica recebe 5000 J de calor de uma fonte quente e realiza trabalho de 3500 J. Calcule o rendimento dessa máquina térmica.
solução:
τ=3500 J
Q1=5000J
η= τ/Q1
η= 3500/5000
η= 0,7 ou seja 70%
Energia dissipada será:
τ = Q1 - Q2
Q2 = Q1- τ
Q2=5000-3500
Q2= 1500 J
Exercicio: Qual seria o rendimento se a máquina do exercicio anterior realizasse 4000J de trabalho com a mesma quantidade de calor fornecida ? Quanta energia seria dissipada agora?
obs: Entregar foto da resolução ou o cálculo passo a passo na mensagem
The density is 19.4 g/ml the units could also be 19.4 g/cm^3