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juin [17]
3 years ago
10

Leave answer in exact form unless otherwise indicated.

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0

Answer:

Looking at the graphic, we see radius OA = 8 inches and chord AB = 8 inches and Line AE = one half of chord AB = 4 inches

From the Pythagorean Theorem, we can then calculate the APOTHEM (Line OE) as: OE^2 = OA^2 - AE^2

OE^2 = 8^2 - 4^2   OE^2 = 64 -16   OE^2 = 48

OE = 6.9282032303 inches

Angle AOE = arc tangent (AE / OE)

Angle AOE = arc tangent (4 / 6.9282032303)

Angle AOE = 30 degrees and Angle AOB = (2 * AOE) = 60 degrees

The area of the sector (red area + green area) = (Angle AOB / 360) * PI * radius^2

Sector Area = (0.1666666667) * PI * 64

Sector Area = 33.5103216067 sq inches

Red Triangle Area = AE * OE = 4 * 6.9282032303 = 27.7128129212 sq inches

Segment Area = Sector Area - Red Triangle Area =

Segment Area = 33.5103216067 -27.7128129212

Segment Area = 5.7975086855 sq inches

Source: https://www.1728.org/circpart.htm


Step-by-step explanation:


Serggg [28]3 years ago
4 0

Answer:

201.06

Step-by-step explanation:

2(pie)(r^2) \ 2

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Answer:

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Step-by-step explanation:

∵ A (-4 , 1) and (2 , 1)

∴ AB is a horizontal segment (same y-coordinates)

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∵ B (2 , 1) and C (2 , -5)

∴ BC is a vertical segment (same x-coordinates)

∴ AB ⊥ BC

∴ BC = 1 - -5 = 6 units

∵ A (-4 , 1) and D (-4 , -3)

∴ AD is a vertical segment

∴ AD ⊥ AB

∴ AD // BC

∴ AD = 1 - -3 = 4 units

∴ ABCD is trapezium with parallel bases AD , BC and height AB

∵ A=\frac{b_{1}+b_{2}}{2}h

∴ A=\frac{4+6}{2}(6)=30 units²

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An earth satellite remains in orbit at a distance of 11550 km from the center of the earth. what speed would it have to maintain
marishachu [46]
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G · m · t² = 4 · π² · r³  we can change that to
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t^2 = 4*PI^2*r^3 / (G*m)
</span>t^2 = 4*PI^2*<span>(11,550,000)^3 / 6.67*10^-11*5.98*10^24kg
t^2 = </span> <span> <span> <span> 6.083*10^22 </span> </span> </span> <span><span> </span> </span> / <span> <span> <span> 3.9</span></span></span>9 * 10^14
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Source:
http://www.1728.org/kepler3a.htm



4 0
4 years ago
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