Answer:
The Answers are

Step-by-step explanation:
Let we Know some Identities
cosec (-θ) = - cosec (θ)
sec (-θ) = sec (θ)
cot (-θ) = - cot (θ)
Also,

Therefore,

Answer:
im pretty sure it is 2
Step-by-step explanation:
Answer:
397.7 m²
Step-by-step Explanation:
Step 1: find m < W
W = 180 - (33+113) (sum of ∆)
W = 34°
Step 2: find side UV using the law of sines


Multiply both sides by sin(34)


(approximated)
Step 3: find the area using the formula, ½*UV*VW*sin(V)
area = ½*29.8*29*sin(113)
Area = 397.7 m² (rounded to the nearest tenth.
Step-by-step explanation: look so if you have
shcool A its 8v+4b=12
and
School B: 12v+4b= 16
since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.
You should find part of the process to be
12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.
Answer -4
Answer: 45
Step-by-step explanation:
Harsh is part of a school cricket team, and he has scored an average of 46 runs in 5 innings. His scores in 4 of them are 46,45, 39, and 55. His fifth score is calculated as follows:
Since he made 5 innings and has an average of 46, the total scores will be:
= 46 × 5
= 230
Total of his first 4 scores will be:
= 46 + 45 + 39 + 55
= 185
5th score = 230 - 185
= 45