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laiz [17]
3 years ago
15

You are examining the DNA sequences that code for the enzyme phosphofructokinase in skinks and Komodo dragons. You notice that t

he coding sequence that actually directs the sequence of amino acids in the enzyme is very similar in the two organisms but that the surrounding sequences vary quite a bit. What is the most likely explanation for this?
A. Coding sequences are repaired more efficiently.
B. Coding sequences are replicated more efficiently.
C. Coding sequences are packaged more tightly in th e chromosomes to protect them from DNA damage.
D. Mutations in coding sequences are more likely to e deleterious to the organism than mutations in noncoding sequences.
E. Recombination between skink and Komodo dragon DNA occurred recently
Biology
1 answer:
sp2606 [1]3 years ago
4 0

Answer:

The correct answer is D.

Explanation:

Mutations in coding sequences are more likely to be deleterious to the organism than mutations in non-coding sequences.

Mutations in coding sequence is more harmful because they end up mutating the protein coding region of the DNA , which alters the function of proteins.

These mutations may cause some harmful genetic disorder or end up causing cancer.  That is why mutations  in coding sequences are more harmful to the organism than mutations in non-coding sequences.

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Which are different forms of the same gene?<br> O genotypes<br> Ophenotypes<br> alleles<br> traits
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The curly toe phenotype is controlled by 4 genes that act in an additive manner. The environment does not have an effect on this
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Answer:

  1. What is the highest number of risk units an individual can have with this model? 48 units of risk
  2. What is the phenotype of an individual of genotype AaBbCCDd? The individual has curly toes
  3. Is it possible for them to have a child with curly toes?

        Yes, the couple can have children with curly toes.

Explanation:

<u>Available data</u>:

  • The curly toe phenotype is controlled by 4 diallelic additive genes
  • Genes A, B, C, D  
  • A dominant allele has 6 units of risk
  • A recessive allele has 2 units of risk
  • Individuals with more than 35 units of risk have curly toes
  • Individuals with 35 or fewer risk units have straight toes

The term quantitative heritability refers to the transmission of a phenotypic trait in which expression depends on the additive effect of a series of genes.  

Polygenic heritability occurs when a trait results from the interaction of more than one gene. And these genes can also have more than two alleles. The action of many genes and alleles can cause many different combinations that are the reason for genotypic graduation.  

Quantitative traits are those that can be measure, such as longitude, weight, eggs laid per female, among others. These characters do not group individuals by any precise and clear categories. Instead, they group individuals in many different categories that depend on how the genes were intercrossed and distributed during meiosis. The result depends on the magnitude in which each allele contributes to the final phenotype and genotype. When they interact, they create a gradation in phenotypes, according to the level of contribution.

According to this information, and knowing how each allele contributes to the risk, we can say that the minimum units of risk are 16, determined by the recessive genotype aabbccdd. Each recessive allele contributes with 2 units of risk, so (aa=4units + bb=4 units + cc=4 units + dd=4 units) =  16 units.

Each time a dominant allele is present in the genotype, it adds 6 units to the total risk.    

What is the highest number of risk units an individual can have with this model?

48 units of risk, which corresponds to the genotype AABBCCDD. Each dominant allele contributes 6 units to the risk. There are 8 dominant alleles, so, 8x6=48 units.

What is the phenotype of an individual of genotype AaBbCCDd?

The individual has curly toes because it has a risk of 36 units, which is superior to the limit of 35 units. Dominant alleles A, B, C, C, D contribute with 30 units of risk (6x5), and recessive alleles a, b, d contribute 6 units of risk (3x2).

Cross:

Parentals) AAbbCcDd   x   AaBbCCDd

Gametes) AbCD, AbcD, AbCd, Abcd

               ABCD, ABCd, AbCD, AbCd, aBCD, aBCd, abCD, abCd

Punnett square)  AbCD                 AbcD               AbCd               Abcd

          ABCD    AABbCCDD     AABbCcDD     AABbCCDd     AABbCcDd

          ABCd    AABbCCDd      AABbCcDd     AABbCCdd      AABbCcdd

          AbCD    AAbbCCDD      AAbbCcDD    AAbbCCDd     AAbbCcDd

         AbCd     AAbbCCDd       AAbbCcDd     AAbbCCdd     AAbbCcdd

         aBCD     AaBbCCDD      AaBbCcDD      AaBbCCDd     AaBbCcDd

         aBCd     AaBbCCDd      AaBbCcDd      AaBbCCdd     AaBbCcdd

         abCD     AabbCCDD      AabbCcDD      AabbCCDd    AabbCcDd

         abCd      AabbCCDd      AabbCcDd      AabbCCdd        AabbCcdd

F1) 16 /32 = 1/2 individuals in the progeny are expected to have curly toes

     16 /32 = 1/2 individuals are expected to have straight toes

Is it possible for them to have a child with curly toes?

Yes, the couple can have children with curly toes.

To have curly toes, individuals must have more than 35 units of risk.

To have more than 35 units, individuals´ genotypes must carry at least 5 dominant alleles (which equal 30 units).

8 0
3 years ago
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