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Umnica [9.8K]
4 years ago
6

The absolute temperature of a sample of monatomic ideal gas is doubled at constant volume. What effect, if any, does this have o

n the pressure and density of the sample of gas? Pressure Density
1. Remains the same Doubles
2. Doubles Multiplied by 4
3. Doubles Remains the same
4. Remains the same Remains the same
5. Multiplied by 4 Doubles
Physics
1 answer:
Tema [17]4 years ago
4 0

Answer:

option (3)

Explanation:

According to the ideal gas equation

PV = nRT

where, P is pressure, V is volume, R is gas constant and T be the absolute temperature.

At constant volume,

P ∝ T

If the temperature is doubled, the pressure also doubled.

As volume is constant, so the density is also constant.

So, the pressure is doubled and the density remain constant.

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Explanation:

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Determine the magnitude and direction of the resultant velocity of 75.0 m/s. 25.0 east of north, and 100.0 m/s, 25.0 east of sou
aleksandr82 [10.1K]

Answer:

77.35 m / s

Ф = -17° from + X axis or 343° from + X axis

Explanation:

v1 = 75 m/s 25° east of north

v2 = 100 m/s  25° east of south

Write the velocities in vector form ,we get

\overrightarrow{v_{1}}=75\left ( Sin25\widehat{i} +Cos25\widehat{j}\right )=31.7\widehat{i}+67.97\widehat{j}

\overrightarrow{v_{1}}=100\left ( Sin25\widehat{i} -Cos25\widehat{j}\right )=42.26\widehat{i}-90.63\widehat{j}

Now add the velocity vectors to get the resultant of the velocities.

\overrightarrow{v}=\overrightarrow{v_{1}}+\overrightarrow{v_{2}}

\overrightarrow{v}=\left (31.7+42.26  \right )\widehat{i}+\left ( 67.97- 90.63 \right )\widehat{j}

\overrightarrow{v}=73.96\widehat{i}-22.66\widehat{j}

magnitude of resultant velocity is \sqrt{\left ( 73.96 \right )^{2}+\left ( -22.66 \right )^{2}}

  = 77.35 m / s

The direction is Ф from X axis

tan\phi =\frac{-22.66}{73.96}=-0.306

Ф = -17° from + X axis or 343° from + X axis

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Your friend is flying a remote control jet in your yard, as seen in the diagram above. As it flies past you, you notice that the
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Explanation:

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