Answer: angular displacement in rad = 3038.45 rad
angular displacement in rev = 483.589 rev
Explanation: mathematically
Angular velocity = angular displacement / time taken.
Angular velocity = 33.5 rad/s, time taken = 90.7s
33.5 = angular displacement /90.7
Angular displacement = 33.5 * 90.7 = 3038.45 rad
But 1 rev =2π
Hence 3038.45 rad to rev is
3038.45/2π = 483.599 rev
Thew energy stored in a capacitor of capacitance
and voltage between the plates
is
.
Substituting numerical value

Answer:
Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force
Explanation:
at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.
Explanation:
It is given that,
Frequency of diagnostic ultrasound, f = 3.82 MHz = 3820 Hz
The speed of the sound in air, v = 343 m/s
(a) We need to find the wavelength in air of such a sound wave. Let it is given by λ₁
i.e. 


(b) If the speed of sound in tissue is 1650 m/s .



Hence, this is the required solution.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The wavelength is
Explanation:
From the question we are told that
The distance of the slit to the screen is 
The order of the fringe is m = 6
The distance between the slit is
The fringe distance is 
Generally the for a dark fringe the fringe distance is mathematically represented as
![Y = \frac{[2m - 1 ] * \lambda * D }{2d}](https://tex.z-dn.net/?f=Y%20%20%3D%20%5Cfrac%7B%5B2m%20%20-%201%20%5D%20%2A%20%20%5Clambda%20%2A%20%20D%20%20%7D%7B2d%7D)
=> ![\lambda = \frac{Y * 2 * d }{[2*m - 1] * D}](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20%5Cfrac%7BY%20%2A%20%202%20%2A%20%20d%20%7D%7B%5B2%2Am%20%20-%20%201%5D%20%2A%20%20D%7D)
substituting values
=> ![\lambda = \frac{0.019 * 2 * 0.9*10^{-3} }{[2*6 - 1] * 5}](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20%5Cfrac%7B0.019%20%2A%20%202%20%2A%20%200.9%2A10%5E%7B-3%7D%20%7D%7B%5B2%2A6%20%20-%20%201%5D%20%2A%20%205%7D)
=> 
