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Illusion [34]
3 years ago
13

A standing wave of the third harmonic is induced in a stopped pipe of length 1.2 m. The speed of sound through the air of the pi

pe is 340 m/s. How many antinodes form in the standing wave pattern in the pipe?
Physics
1 answer:
stira [4]3 years ago
7 0

Answer:

Answer is 3.

Explanation:

Start by putting the values in the formula i.e.

Lenght 1.2m

The speed of sound through the pipe 340m/s.

Put it in the formula and the answer is 3.

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During the spin cycle of your clothes washer, the tub rotates at a steady angular velocity of 33.5 rad/s. Find the angular displ
zavuch27 [327]

Answer: angular displacement in rad = 3038.45 rad

angular displacement in rev = 483.589 rev

Explanation: mathematically

Angular velocity = angular displacement / time taken.

Angular velocity = 33.5 rad/s, time taken = 90.7s

33.5 = angular displacement /90.7

Angular displacement = 33.5 * 90.7 = 3038.45 rad

But 1 rev =2π

Hence 3038.45 rad to rev is

3038.45/2π = 483.599 rev

7 0
3 years ago
Read 2 more answers
A 6.00-μf parallel-plate capacitor has charges of 40.0 μc on its plates. how much potential energy is stored in this capacitor?
dedylja [7]

Thew energy stored in a capacitor of capacitance C and voltage between the plates V is

E=\frac{1}{2} CV^2=\frac{1}{2C} Q^2.

Substituting numerical value

E=\frac{1}{2*6*10^{-6}} (40*10^{-6})^2\\ E=133.33\; \mu J

7 0
3 years ago
Define the term work​
bagirrra123 [75]

Answer:

Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force

Explanation:

at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.

5 0
2 years ago
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Diagnostic ultrasound of frequency 3.82 MHz is used to examine tumors in soft tissue. (a) What is the wavelength in air of such
maxonik [38]

Explanation:

It is given that,

Frequency of diagnostic ultrasound, f = 3.82 MHz = 3820 Hz

The speed of the sound in air, v = 343 m/s

(a) We need to find the wavelength in air of such a sound wave. Let it is given by λ₁

i.e. \lambda=\dfrac{v}{\nu}

\lambda_1=\dfrac{343\ m/s}{3820\ Hz}

\lambda_1=0.089\ m

(b) If the speed of sound in tissue is 1650 m/s .

\lambda_2=\dfrac{v}{\nu}

\lambda_2=\dfrac{1650\ m/s}{3820\ Hz}

\lambda_2=0.43\ m

Hence, this is the required solution.

7 0
3 years ago
What is the wave length if the distance from the central bright region to the sixth dark fringe is 1.9 cm . Answer in units of n
Yuri [45]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  wavelength is  \lambda  =  622 nm

Explanation:

  From the question we are told that

    The distance of the slit to the screen is  D  = 5 \ m

    The order of the fringe is m  =  6

     The distance between the slit is  d = 0.9 \ mm  =  0.9 *10^{-3} \ m

    The fringe distance is  Y =  1.9 \ cm  =  0.019 \ m

Generally the for a dark fringe the fringe distance is  mathematically represented as

        Y  = \frac{[2m  - 1 ] *  \lambda *  D  }{2d}

=>     \lambda  =  \frac{Y *  2 *  d }{[2*m  -  1] *  D}

substituting values

=>      \lambda  =  \frac{0.019 *  2 *  0.9*10^{-3} }{[2*6  -  1] *  5}

=>     \lambda  =  6.22 *10^{-7} \ m

       \lambda  =  622 nm

8 0
2 years ago
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