Hey there mate ;)
Given PPT image question is attached.
For answers :-
☆ The spectators in the stand are like particles in a <em><u>solid</u></em><em> </em>because <em><u>the</u></em><em><u> </u></em><em><u>spectators</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>sitting</u></em><em><u> </u></em><em><u>very</u></em><em><u> </u></em><em><u>close</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>each</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>no</u></em><em><u> </u></em><em><u>spaces</u></em><em><u> </u></em><em><u>in between</u></em><em><u> </u></em><em><u>them</u></em><em><u>,</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>property</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>solids</u></em><em><u>. </u></em>
☆ The players in the pitch are like particles in a <em><u>gas</u></em><em> </em>because <em><u>there</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>large</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>if</u></em><em><u> </u></em><em><u>space</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>between</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>players</u></em><em><u>,</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>property</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>gases</u></em><em><u>.</u></em>
☆ The spectators standing in the terraces are like particles in a <em><u>liquid</u></em> because <em><u>there is </u></em><em><u>little</u></em><em><u> space in between the spectators, which is like a property of liquid.</u></em>
To find the average (aka mean) of a group of numbers, all we need to do is add them up then divide that number by how many numbers we started with
23 + 21 + 24 + 22 = 90
90 ÷ 4 = 22.5
Therefore, the average distance the book traveled on ice is 22.5 cm
15 + 18 + 16 + 17 = 66
66 ÷ 4 = 16.5
Therefore, the average distance the book traveled on concrete is 16.5 cm
In conclusion, the average distance the book traveled on ice is greater than the average distance the book traveled on concrete
Hope this helps you
-AaronWiseIsBae
I showed my working in the images above. if you have any questions please feel free to ask
Explanation:
PE= mgh
6 J= (3m) (9.81 m/s2) (mass)
mass=( 6)/(3×9.81)
mass= 0.20 Kg
Answer : Celestial or azimuth - altitude
Explanation :
Celestial : The celestial coordinates that are analogous to longitude and latitude are called RA and Dec.
RA = Right Ascension
Dec = Declination
RA is the measured in unit of time and Dec is measured in degree.
The equatorial coordinate system is the projection of the latitude and longitude coordinate system on the celestial sphere.
Azimuth - altitude : Azimuth - altitude define the location of an object in the sky.
The altitude is the distance of an object appears to be above the horizon.
The Azimuth of the object is the angular distance along the horizon to the location of the object.