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Jet001 [13]
3 years ago
9

In a collision an object experiences impulses , this impulse can be determined by

Physics
1 answer:
astraxan [27]3 years ago
8 0

In a collision an object experiences impulses, this impulse can be determined by the product of net force exerted upon it in the specific course of time.

<u>Explanation:</u>

An object experiences impulse due to the force exerted upon it in a particular time period.

i.e.

                 \text {Impulse }=F \times \Delta t

Where,

F - Force acted upon the object

\Delta t - time interval for which the force act

According to the definition of Impulse, it is the integral of force (F) that acts upon any object over a time interval ∆t. It produces an equivalent change in the momentum and that too in the same direction as of the applied force (F).

Therefore, in order to find the impulse on an object, we have to find the force acted on it in a specific time interval.

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A crane lifts a 100 kg concrete block to a vertical height of 25 m. Calculate
Nana76 [90]

Answer:

Solon,

total mass (kg)= 100kg

height (h)= 25m

acceleration due to gravity = 9.8m/s²

so,

work done =m*g*h

= 100*9.8*25

= 24,500 joule

5 0
3 years ago
Two small objects are suspended from threads. When the objects are moved close together, they attract one another. What of the f
creativ13 [48]

Answer:d

Explanation:

All the given situations are possible because

(a)When particles are oppositely charged then they attract each other

(b)One is Positively charged and other is uncharged: Charged particle will induce charges of opposite nature to attract the other particle

(c)Negatively charged particles will induce the positive charge in the uncharged particle to attract the initially uncharged particle.

                 

4 0
3 years ago
(b) Suppose at a certain instant the kinetic energy is twice the elastic potential energy. Write an equation describing this sit
timurjin [86]

Answer:

1/2mv² = ke²

Explanation:

Let's suppose the material in question is a spring with spring constant k, mass m and position k, the kinetic energy possessed by the string will be;

K.E = 1/2mass×velocity² i.e 1/2mv²

Its elastic potential energy will be the work done on the spring when stretched which is equal to 1/2kx²

E.P = 1/2kx²

The equation describing the case where the kinetic energy is twice the elastic potential energy will be;

K.E = 2EP... 1)

Substituting the KE and EP formula into (1), we have;

1/2mv² = 2(1/2ke²)

1/2mv² = ke² which gives the required equation

8 0
3 years ago
What is the velocity of a wave with a wavelength of 9 meters and a period of 0.006
Ipatiy [6.2K]

Answer: 1,500m/s

Explanation:

Relationship existing between velocity of a wave (v), wavelength(¶) and frequency(f) is

v = f¶... (1)

Since Frequency (f) is the reciprocal of the period (T);

Frequency = 1/Period i.e F = 1/T... (2)

Substituting equation 2 into 1 we have;

v = 1/T × ¶

v = ¶/T

Given wavelength ¶ = 9m

Period T = 0.006s

v = 9/0.006

v = 1,500m/s

The velocity of the wave will be 1,500m/s

8 0
3 years ago
A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is ne
Charra [1.4K]

Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.

Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are

W_x = 500 cos37

W_y = 500 sin37

now here as we can say that one of the component is balanced here by the normal force perpendicular to plane

while the other component of the weight is balanced by the force applied on the rope

So here the force applied on the rope will be given as

F = W_y = 500 sin37

F = 300 N

so it apply 300 N force along the inclined plane

5 0
3 years ago
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