Answer:
See the answe below, please.
Explanation:
In the stomach, during digestion there are two types of:
-Mechanics: the degradation of food occurs, distension of the stomach walls is performed when they arrive, producing the Chyme.
Chemistry: through the participation of enzymes (pepsin activated by hydrochloric acid, which digests proteins in shorter amino acid chains and; gastric lipase that breaks fat giving glycerin products and fatty acids)
They have similar electron configurations and have similar ionic chargers
Answer: m= 0.69 m or mol/kg
Explanation: Molality is expressed as moles per unit kilograms of solvent or m= n / kg
First convert 25.0 g NaCl to moles
25.0 g NaCl x 1 mole NaCl / 58 g NaCl
= 0.43 moles NaCl
Next convert 625 g H2O to kilograms
625 g H2O x 1 kg / 1000 g H2O
= 0.625 kg H2O
Substitute the values in the formula
m = n / kg
= 0.43 mole NaCl / 0.625 kg
= 0.69 m or mole / kg
Answer:
The theoretical yield of Cu(s) in moles is 60.15 moles
Explanation:
Step 1: Data given
Number of moles CuO = 70.8 moles
Number of moles NH3 = 40.1 moles
Molar mass CuO = 79.545 g/mol
Molar mass NH3 = 17.03 g/mol
Step 2: The balanced equation
3CuO(s) + 2NH3(g) → 3H2O(l) + 3Cu(s) + N2(g)
For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2
NH3 is the limiting reactant. It will completely be consumed (40.1 moles). CuO is in excess. There will react 3/2 * 40.1 = 60.15 moles
There will remain 70.8 - 60.15 = 10.65 moles CuO
Step 3: Calculate moles Cu
For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2
For 40.1 moles NH3 we'll have 60.15 moles Cu
The theoretical yield of Cu(s) in moles is 60.15 moles
Propylethylene would be the answer
