You are a NASCAR pit crew member. Your employer is leading the race with 20 laps to go. He just finished a pit stop and has 5.0
1 answer:
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<h2>Answer:</h2>
44.06 g/mol
<h3>Explanation:</h3>We are given;
- Number of moles of unidentified gas as 1.674×10^-4 mol
- Time of effusion of unidentified gas 86.6 s
- Number of moles of Argon gas as 1.715×10^-4 mol
- Time of effusion of Argon gas is 84.5 s
We are supposed to calculate the molar mass of unidentified gas
<h3>Step 1: Calculate the effusion rates of each gas</h3>Effusion rate = Number of moles/time
Effusion rate of unidentified gas (R₁)
= 1.674×10^-4 mol ÷ 86.6 s
= 1.933 × 10^-6 mol/s
Effusion rate of Argon gas (R₂)
= 1.715×10^-4 mol ÷ 84.5 sec
= 2.030 × 10^-6 mol/s
<h3>Step 2: Calculate the molar mass of unidentified gas</h3>- Assuming the molar mass of unidentified gas is x;
- We can use the Graham's law of effusion to find x;
- According to Graham's law of diffusion;
But, Molar mass of Argon is 39.948 g/mol
Therefore;
Solving for X
x = 44.06 g/mol
Therefore, the molar mass of the identified gas is 44.06 g/mol
Answer:
Lithium diisopropylamide [(CH3)2CH]2NLi.
Explanation:
Lithium diisopropylamide (commonly abbreviated LDA) is a chemical compound with the molecular formula [(CH3)2CH]2NLi. It is used as a strong base and has been widely accepted due to its good solubility in non-polar organic solvents and non-nucleophilic nature. It is a colorless solid, but is usually generated and observed only in solution. It was first prepared by Hamell and Levine in 1950 along with several other hindered lithium diorganylamides to effect the deprotonation of esters at the α position without attack of the carbonyl group.
