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artcher [175]
3 years ago
12

Can someone help me with these questions?

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0
1) 1, -2..for the first question
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Solve the quadratic equation 4x2 − 121 = 0. Verify your answer using a difference-of-squares factoring method.
Alenkasestr [34]

Answer:

Option d) is correct

That is x equals plus or minus start fraction 11 over two end fraction

Step-by-step explanation:

Given quadratic equation is 4x^2-121=0

To write the given quadratic equation by using a difference-of-squares factoring method:

4x^2-121=0

The above equation can be written as

4x^2-11^2=0

(2x)^2-11^2=0

The above equation is in the form of difference-of-squares

Therefore the given quadratic equation can be written in the form of difference-of-squares

by factoring method is (2x)^2-11^2=0

(2x+11)(2x-11)=0 (which is in the form a^2-b^2=(a+b)(a-b) )

2x+11=0   or   2x-11=0

x=\frac{-11}{2}    or   2x=11

x=\frac{-11}{2}    or   x=\frac{11}{2}

x=\pm \frac{11}{2}

Therefore option d) is correct

That is x equals plus or minus start fraction 11 over two end fraction

5 0
3 years ago
What is the midpoint of 2,-6 and -8,5
Readme [11.4K]

Step-by-step explanation:

midpoint = ( \frac{2 - 8}{2} ,  \frac{ - 6 + 5}{2} )

= ( \frac{ - 6}{2} , \frac{ - 1}{2} )

= ( - 3, - 0.5)

6 0
3 years ago
Read 2 more answers
Find the slope of the line
Elza [17]

Answer:

-3'1

-6'1

Step-by-step explanation:

the bottom left and top right are always going to be negative. The right top and bottom are positive numbers. so the answer is -3'1 for the first top one then the second bottom dot is -6'1

8 0
3 years ago
3x+3 gbggggggggggggggggggggg
ella [17]

Answer:

I think it is 3(x+1) not sure but try it(it is a graph answer)

7 0
3 years ago
DG¯¯¯¯¯¯ , EG¯¯¯¯¯ , and FG¯¯¯¯¯ are perpendicular bisectors of the sides of △ABC . DG=5 cm and BD=12 cm.
jonny [76]
Given that <span>DG, EG, and FG are perpendicular bisectors of the sides of △ABC, this means that the point of intersection, G, is the circumcenter of the triangle and hence A</span><span>G, BG, and CG are equal.

Given that </span><span>DG = 5 cm and BD = 12 cm, then

BG= \sqrt{DG^2+BD^2}  \\  \\ = \sqrt{5^2+12^2} = \sqrt{25+144}  \\  \\ = \sqrt{169} =13

Since AG = BG = CG, therefore, CG = 13 cm.</span>
3 0
3 years ago
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