Food that people eat provides us with what that we need to survive?

How many hybrid orbitals do we use to describe each molecule c2h5no (4 c−h bonds and one o−h) key?

yarga [219]

Answer:

see attached

Explanation:

6 0

3 years ago

Ordinary water boils at 100°C. Can it be made to boil at 95°C or 105°C.

slava [35]

It can be done. Normally the boiling point of water is 100°C. It will boil at temperature greater than 100°C more quickly. Water can be boiled at 95°C but for that the atmospheric pressure of the water should be decreased which will decrease the boiling point of water.

<h3>Concept :</h3>

To boil water at 95°C, decrease the atmospheric pressure.

At 105°C, the water will be boiling quickly than normal at 100°C.

4 0

1 year ago

Read 2 more answers

Which scenario would result in a population growth of zero? Use this formula: population growth = (birth rate + immigration) – (

swat32

Answer:

12 individuals are born 10 individuals emigrate, 4 individuals die, 14 individuals immigrate, 0 individuals are born

Explanation:

From the formula:

Population growth = (birth rate + immigration) – (death rate + emigration)

= (b + i) - (d + e)

<em>For the first option, b = 12, i = 0, d = 12, e = 12</em>

population growth = (12+0) - (12+12) = -12

<em>For the second option: b = 13, i = 0, d = 3, e = 16</em>

population growth = (13+0) - (3+16) = -6

<em>For the third option: b = 12, i = 20, d = 0, e = 8</em>

population growth = (12+20) - (0+8) = 24

<em>For the last option: b = 0, i = 14, d = 4, e = 10</em>

population growth = (0+14) - (4+10) = 0

Hence, the last option is the correct option.

8 0

2 years ago

Read 2 more answers

What is the bond order of li2−? express the bond order numerically?

jeka94

Atomic Number of Lithium is 3, so it has 3 electrons in its neutral state. Also, Li₂ will have 6 electrons. But the chemical formula we are given has a negative charge on it (i.e Li₂⁻) so there is an additional electron (RED) present on this compound. So, the total number of electrons are 7. The MOT diagram for this compound is shown below. According to diagram we are having 4 electrons in Bonding Molecular Orbitals (BMO) and 3 electrons in Anti-Bonding Molecular Orbitals (ABMO). Bond Order is calculated as,

Bond Order = (# of e⁻s in BMO - # of e⁻s in ABMO) ÷ 2

Bond Order = (4 - 3) ÷ 2

Bond Order = 1 ÷ 2
Or,
Bond Order = 1/2
Or,
Bond Order = 0.5

4 0

3 years ago

Compare which element would have larger first ionization energy: an alkali metal in Period 2 or an alkali metal in Period 4?

maria [59]

Answer:

An alkali metal present in period 2 have larger first ionization energy.

Explanation:

Ionization energy:

The amount of energy required to remove the electron from the atom is called ionization energy.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus. Thus alkali metal present in period 2 have larger ionization energy because of more nuclear attraction as compared to the alkali metal present in period 4.

6 0

2 years ago