Food that people eat provides us with what that we need to survive?

Atmospheric pressure at sea level is equal to a column of 760 mm Hg. Oxygen makes up 21 percent of the atmosphere by volume. The

Neporo4naja [7]

Answer: The partial pressure of oxygen is 160 mmHg

Explanation:

We are given:

Percent of oxygen in air = 21 %

Mole fraction of oxygen in air = $\frac{21}{100}=0.21$

To calculate the partial pressure of oxygen, we use the equation given by Raoult's law, which is:

$p_{O_2}=p_T\times \chi_{O_2}$

where,

$p_{O_2}$ = partial pressure of oxygen = ?

$p_T$ = total pressure of air = 760 mmHg

$\chi_{O_2}$ = mole fraction of oxygen = 0.21

Putting values in above equation, we get:

$p_{O_2}=760mmHg\times 0.21\\\\p_{O_2}=160mmHg$

Hence, the partial pressure of oxygen is 160 mmHg

8 0

3 years ago

Which of the following would DECREASE the rate of a reaction?

tia_tia [17]

Answer: increasing volume

Explanation: adding a catalyst would increase reaction time and increasing INCREASING concentration definently makes reaction time alot faster increasing pressure actually makes it more concentrated, so no it is not

8 0

3 years ago

What is the rate constant of a reaction if rate = 0.2 (mol/L)/s, [A] and [B] are each 3 M, m = 1, and n = 2?

tino4ka555 [31]

M= 1 and n = 2
( m+ n = 1 +2 = 3)

rate = K [A] [B]^2

0.2 = K * 3 * 3 ^2
0.2 = K * 3 * 9
K = 0.2 / 27
K = 7.408 * 10 ^ -3 m^-2 s^-1

4 0

3 years ago

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Based of the chemical reaction below, if you have 3.56x10^23 molecules of C3H8, how many liters of CO2 gas will be produced at S

LenaWriter [7]

Answer:

39.65L

Explanation:

First, let us calculate the number of mole present in 3.56x10^23 molecules of C3H8.

1 mole of any substance contains 6.02x10^23 molecules as discovered from Avogadro's hypothesis. This means that 1mole of C3H8 contains 6.02x10^23 molecules.

Now, if 1mole of C3H8 contains 6.02x10^23 molecules, then Xmol of C3H8 will contain 3.56x10^23 molecules i.e

Xmol of C3H8 = 3.56x10^23/6.02x10^23 = 0.59mole

The equation for the reaction is given below:

C3H8 + 5O2 —> 3CO2 + 4H2O

From the equation above,

1 mole of C3H8 produced 3moles of CO2.

Therefore, 0.59mole of C3H8 will produce = 0.59 x 3 = 1.77mole of CO2.

Now let us calculate the volume occupied by 1.77mole of CO2. This is illustrated below:

1 mole of any gas occupy 22.4L at stp.

Therefore, 1.77mole of CO2 will occupy = 1.77 x 22.4 = 39.65L

Therefore, 39.65L of CO2 are produced.

5 0

4 years ago

Uranium-236 is ____.

wolverine [178]

Answer: The correct answer is a.

Uranium-236 is intermediate nuclei created by fusion reactions an unstable isotopes of uranium created from four hydrogen atoms used in the H - bomb .

Following is the reaction involved in above process :

²³⁵U + ¹n = ²³⁶U = ¹⁴⁴Ba + ⁸⁹ Kr + 3¹n + 177 MeV

Here ,

²³⁵U = Fision Material ,

¹n = projectile ,

²³⁶U = Intermediate Nuclei

¹⁴⁴Ba and ⁸⁹ Kr = Fission product

Explanation:

hope it helps !

brainliest plzz :)))

3 0

3 years ago

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