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2 years ago

How are oxonium salts formed?with reaction

Chemistry

1 answer:

JulijaS [17]2 years ago

6 0

Answer:

It's a salt formed by the reaction of an acid with an organic compound containing a basic oxygen atom.

Explanation:

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Rank the compounds in each set in order of increasing acid strength.

Viktor [21]

Answer:

See explanation

Explanation:

For this question, we have to remember the effect of an atom with high electronegativity as "Br". If the "Br" atom is closer to the carboxylic acid group (COOH) we will have an inductive effect. Due to the electronegativity of Br, the electrons of the C-H bond would be to the Br, then this bond would be weaker and the compound will be more acid (because is easier to produce the hydronium ion $H^+$ ).

With this in mind, for A in the last compound, we have 2 Br atoms near to the acid carboxylic group, so, we will have a high inductive effect, then the C-H would be weaker and we will have more acidity. Then we will have the compound with only 1 Br atom and finally, the last compound would be the one without Br atoms.

In B, the difference between the molecules is the position of the "Br" atom in the molecule. If the Br atom is closer to the acid group we will have a higher inductive effect and more acidity.

See figure 1

I hope it helps!

5 0

3 years ago

Can someone help me plz. I will mark them Brainliest.

Sveta_85 [38]

See photo for answer

8 0

2 years ago

If you have 1 proton and 2 electrons, what is the overall charge of the ion?

marysya [2.9K]

The overall charge will be negative 1

4 0

3 years ago

A mixture of MgCl2 and NaCl has an initial mass of 0.4015 g. Excess AgNO3(aq) was added and 1.032 g of precipitate, AgCl(s), was

zlopas [31]

Answer:

8.909*10^-4 moles

Explanation:

The mixture contains MgCl $_{2}$ and NaCl with a total mass of 0.4015 g. The mass of precipitate AgCl(aq) is 1.032 g and it has a molar mass of 143.32 g/mol. Therefore, the moles of the precipitate is:

n = 1.032/143.32 = 7.2007*10^-3 moles

Molar mass of NaCl = 58.44 g/mol and the molar mass of MgCl $_{2}$ is 95.21 g/mol. Let the mass (g) of MgCl $_{2}$ in the original mixture be 'x'. Thus:

7.2007*10^-3 = (0.4015-x)/58.44 + 2x/95.21

(7.2007*10^-3)*58.44*95.21 = 95.21(0.4015-x) + 2x(58.44)

40.06505 = 38.227 -95.21x + 116.88x

40.06505 - 38.227 = -95.21x + 116.88x

1.83805 = 21.67x

x = 1.83805/21.67 = 0.0848 g

moles of MgCl $_{2}$ = 0.0848g/95.21 g/mol = 8.909*10^-4 moles

4 0

3 years ago

The weight of Patterson on the moon will be ..... This is 6th grade science by the way

Anestetic [448]

Answer:The weight of Patterson on the moon would be less.

Explanation: It would be less because the moon has more mass.

7 0

3 years ago

How are oxonium salts formed?with reaction​

How are oxonium salts formed?with reaction