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dem82 [27]
3 years ago
11

How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O? The reaction is:

Chemistry
1 answer:
mash [69]3 years ago
3 0
1) The equation is already balanced;

Left side: 1C, 2H and 1O
Right side: 1C, 1O, 2H

2) Starting substances: water and carbon
There are two starting substances also called reactants. H2O which is a compound and C which is an element.

3) Ending substance asked for: H2.

This is hydrogen gas.

Stoichiometry:

1 mol of C produces 1 mol of H2

12.01 g of C productes 2.016 grams of H2

Ratio: 2.016 g of H2 / 12.01 g of C = X g of H2 /  34 g of C =>

x = 34 g of C* 2.016 g of H2 / 12.01 g of C= 5.707 g of H2

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helium gas in a 2.00 L cylinder is under 1.12 atm pressure. At 36.5°C that same gas sample has a pressure of 2.56 atm. What was
Irina18 [472]

Answer:

T₁ = 135.41 K

Explanation:

Given data:

Initial pressure = 1.12 atm

Finial temperature = 36.5 °C (36.5 +273 = 309.5 K)

Initial temperature = ?

Final pressure = 2.56 atm

Formula:  

P₁/T₁ = P₂/T₂  

P₁ = Initial pressure

T₁ = Initial temperature

P₂ = Final pressure

T₂ = Final temperature

Solution:

P₁/T₁ = P₂/T₂  

T₁  = P₁T₂  /P₂

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T₁ = 346.64 atm . K / 2.56 atm

T₁ = 135.41 K

5 0
3 years ago
A 62.6-gram piece of heated limestone is placed into 75.0 grams of water at 23.1°C. The limestone and the water come to a final
alekssr [168]

Answer:

208.7°C was the initial temperature of the limestone.

Explanation:

Heat lost by limestone will be equal to heat gained by the water

-Q_1=Q_2

Mass of limestone = m_1=62.6 g

Specific heat capacity of limestone = c_1=0.921 J/g^oC

Initial temperature of the limestone = T_1=?

Final temperature = T_2=T =  51.9°C

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.0 g

Specific heat capacity of water= c_2=4.186 J/g^oC

Initial temperature of the water = T_3=23.1^oC

Final temperature of water = T_2=T =  51.9°C

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(62.6 g\times 0.921 J/g^oC\times (51.9^oC-T_1))=75.0 g\times 4.186 J/g^oC\times (51.9^oC-23.1^oC)

T_1=208.7^oC

208.7°C was the initial temperature of the limestone.

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3 years ago
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Answer:

It is a combination reaction; nitrogen and hydrogen combine to form ammonia.

Explanation:

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