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3 years ago

How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O? The reaction is:

1 answer:

3 0

1) The equation is already balanced;

Left side: 1C, 2H and 1O
Right side: 1C, 1O, 2H

2) Starting substances: water and carbon
There are two starting substances also called reactants. H2O which is a compound and C which is an element.

3) Ending substance asked for: H2.

This is hydrogen gas.

Stoichiometry:

1 mol of C produces 1 mol of H2

12.01 g of C productes 2.016 grams of H2

Ratio: 2.016 g of H2 / 12.01 g of C = X g of H2 / 34 g of C =>

x = 34 g of C* 2.016 g of H2 / 12.01 g of C= 5.707 g of H2

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Boyle’s law relates to volume and?

fgiga [73]

Answer:

pressure

Explanation:

Boyle's law states that "the volume of a given mass of gas is inversely proportional to the pressure provided the temperature remains constant"

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3 years ago

What is the density of water if you have 50.0 grams of water and a volume of 50.0 millimeters

Gnom [1K]

Answer:

$\boxed {\tt 1.0 \ g/mL}$

Explanation:

Density can be found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the water is 50.0 grams.

The volume of the water is 50.0 milliliters.

$m= 50.0\ g \\v=50.0 \ mL$

Substitute the values into the formula.

$d=\frac{50.0 \ g}{50.0 \ mL}$

Divide.

$d= 1.0 \ g/mL$

The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³

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3 years ago

You can obtain a rough estimate of the size of a molecule with the following simple experiment: Let a droplet of oil spread out

mina [271]

Answer:

The diameter of the oil molecule is $4.4674\times 10^{-8} cm$ .

Explanation:

Mass of the oil drop = $m=9.00\times 10^{-7} kg$

Density of the oil drop = $d=918 kg/m^3$

Volume of the oil drop: v

$d=\frac{m}{v}$

$v=\frac{m}{d}=\frac{9.00\times 10^{-7} kg}{918 kg/m^3}$

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a = $4\pi r^2$

$a=4\times 3.14\times (0.418 m)^2=2.1945 m^2$

Volume of the oil drop = v = Area × thickness

$\frac{9.00\times 10^{-7} kg}{918 kg/m^3}=2.1945 m^2\times x$

$x= 4.4674\times 10^{-10} m= 4.4674\times 10^{-8} cm$

The thickness of the oil drop is $4.4674\times 10^{-8} cm$ and so is the diameter of the molecule.

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3 years ago

0.352 g sample of a diprotic acid is dissolved in water and titrated with 0.150 M NaOH.0.150 M NaOH. What is the molar mass of t

Aliun [14]

<h3>Answer:</h3>

128.94 g/mol

<h3>Explanation:</h3>

Given;

Mass of diprotic acid, H₂X =0.352 g

Molarity of NaOH = 0.150 M

Volume of the NaOH = 36.4 mL

We are required to calculate the molar mass of the acid.

Note: A diprotic acid is an acid that contains 2 replaceable hydrogen atoms

<h3>Step 1: Write the balanced equation fro the reaction;</h3>

The balanced equation for the reaction between the diprotic acid and NaOH will be;

H₂X(aq) + 2NaOH(aq) → Na₂X(aq) + 2H₂O(l)

<h3>Step 2: Determine the number of moles of NaOH used </h3>

Given the molarity and volume of NaOH we can calculate the number of moles;

Moles of NaOH = Molarity × Volume

= 0.150 M × 0.0364 L

= 0.00546 moles

<h3>Step 3: Use the mole ratio to determine moles of the acid </h3>

From the equation;

1 mole of the acid reacts with 2 moles of NaOH

Therefore; H₂x : NaOH = 1 : 2

Moles of H₂x = 0.00546 moles ÷ 2

= 0.00273 moles

<h3>Step 4: Determine the molar mass of the acid.</h3>

Molar mass is the mass equivalent to 1 mole of a compound or element

From our calculations;

0.00273 moles = 0.352 g of the acid;

Therefore, mass in 1 mole ;

= 0.352 g ÷ 0.00273 moles

= 128.94 g/mol

Thus, the molar mass of the diprotic, H₂X is 128.94 g/mol

7 0

3 years ago

Using the word bank below label the wave.

lesya692 [45]

Answer: crest I don’t really know how to explain it but yea it’s crest

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2 years ago

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