Question

A thermodynamic system undergoes a process in which its internal energy decreases by 1,477 J. If at the same time 678 J of thermal energy is transferred to it, how much work (in J) is done by the system?

Answer 1

Answer:2155 J

Explanation:

Given

Change in Internal energy $\Delta U=-1477 J$ i.e. decrease in Internal Energy

Heat added to system $Q=678 J$

According First law for a system

$dQ=dU+dW$

$678=-1477+dW$

$dW=2155 J$

Thus 2155 J of work is done by system