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3 years ago

Which type of energy is transferred by convection currents?

Physics

2 answers:

Masteriza [31]3 years ago

7 0

Answer: thermal

Explanation:
Moving particles transfer thermal energy through a fluid by forming convection currents.

Aleksandr [31]3 years ago

7 0

Answer:

b- thermal

Explanation:

i did it on edge! ; )

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A 0.75 kg book is pushed across the table with an acceleration of 0.3 m/s2. What force is being applied to the

Brums [2.3K]

Answer:

$\boxed {\boxed {\sf 0.225 \ Newtons}}$

Explanation:

We are asked to find the force being applied to a book. According to Newton's Second Law of Motion, force is the product of mass and acceleration.

$F= ma$

The mass of the book is 0.75 kilograms and the acceleration is 0.3 meters per square second. Substitute these values into the formula.

m= 0.75 kg
a= 0.3 m/s²

$F= 0.75 \ kg * 0.3 \ m/s^2$

Multiply.

$F =0.225 \ kg * m/s^2$

1 kilogram meter per second squared is equal to 1 Newton. Therefore, our answer of 0.225 kilogram meters per second squared is equal to 0.225 Newtons.

$F= 0.225 \ N$

0.225 Newtons of force are applied to the book.

5 0

3 years ago

A gry is an old English measure for length, defined as 1/10 of a line, where line is another old English measure for length, def

Valentin [98]

Answer:

0.2448 point²

Explanation:

1 gry = 1/10 line

1 line = 1/12 inch

=> 1 gry in inches = 1/10 * 1/12 = 1/120 inch

=> 1 inch = 120 gry

1 point = 1/72 inch

=> 1 inch = 72 points

Therefore,

120 gry = 72 points

=> 1 gry = 3/5 point

Therefore,

1 gry² = (3/5)² point²

1 gry² = 9/25 point²

This means that 0.68 gry² will be:

0.68 gry² = 0.68 * 9/25 point²

=> 0.68 gry² = 0.2448 point²

6 0

3 years ago

Add a vector whose magnitude is 13 with angle 27 degrees to one whose magnitude is 11 with angle 45 degrees? Put the length firs

mafiozo [28]

Answer:

Magnitude of the vector is $23.75\ \text{units}$ and the direction is $35.23^{\circ}$

Explanation:

Magnitude of first vector = $|A| = 13\ \text{units}$

Angle = $\theta_1=27^{\circ}$

Magnitude of second vector = $|B| = 11\ \text{units}$

Angle = $\theta_2=45^{\circ}$

x component of first vector

$A_{x}=|A|\cos\theta_1\\\Rightarrow A_x=13\cos27^{\circ}\\\Rightarrow A_x=11.6\ \text{units}$

y component of first vector

$A_{y}=|A|\sin\theta_1\\\Rightarrow A_y=13\sin27^{\circ}\\\Rightarrow A_y=5.9\ \text{units}$

x component of second vector

$B_{x}=|B|\cos\theta_2\\\Rightarrow B_x=11\cos45^{\circ}\\\Rightarrow B_x=7.8\ \text{units}$

y component of first vector

$B_{y}=|B|\sin\theta_2\\\Rightarrow B_y=11\sin45^{\circ}\\\Rightarrow A_y=7.8\ \text{units}$

Adding the magnitudes

$C_x=A_x+B_x=11.6+7.8\\\Rightarrow C_x=19.4\ \text{units}$

$C_y=A_y+B_y=5.9+7.8\\\Rightarrow C_y=13.7\ \text{units}$

Magnitude of the sum of the vectors would be

$|C|=\sqrt{C_x^2+C_y^2}\\\Rightarrow |C|=\sqrt{19.4^2+13.7^2}=23.75\ \text{units}$

The direction would be

$\theta=\tan^{-1}\dfrac{C_y}{C_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{13.7}{19.4}\\\Rightarrow \theta=35.23^{\circ}$

The magnitude of the vector is $23.75\ \text{units}$ and the direction is $35.23^{\circ}$

4 0

2 years ago

The majority of the nitrogen on earth can be found in which reservoirs?

xz_007 [3.2K]

Answer:

atmosphere

Explanation:

majority of nitrogen found in atmosphere,it's about 78% and present in form of gas

8 0

2 years ago

How do you calculate the fundamental frequency of a pipe?

ankoles [38]

This depends on whether the pipe is closed or open ended.

The fundamental frequency of a pipe is the simplest, smallest portion of a wave that can fit into a pipe. At the open end of a pipe, there is always an antinode - an area with maximum air movement.

If it is an open ended pipe, there is an antinode at each end, meaning that the length of the pipe is equal to 1/2 λ . Manipulating the formula v=fλ to solve for the fundamental frequency leaves us with f=v/2L in an open ended pipe.

5 0

3 years ago