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balu736 [363]
3 years ago
6

A bowling ball has a mass of 10 kilograms. A tennis ball has a mass of 0.08 kilogram. How much inertia does the bowling ball hav

e compared to the tennis ball?
Newton's First Law is asked to be used here.
Physics
1 answer:
Ede4ka [16]3 years ago
6 0

Answer:

A bowling ball has a mass of 10 kilograms. A tennis ball has a mass of 0.08 kg. How much inertia does the bowling ball have compared to the tennis ball? 10 kg - 0.08 kg = 10.80 kg Since the bowling ball has more mass, naturally it has more inertia since inertia is a quantity that is solely dependent upon the mass

Explanation:

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A 7-n vector at an angle of 45° to the horizontal has a vertical component that is about _______.
Katarina [22]
Vectors are easy once you break them down the right way.

Here is a shortcut formula i have got for you to use to find the x & y components of any vecor, once you know the magnitude and angle (theta):

to find the x component, use<em>:
[magnitude] * cos(theta)

to find the y component use:
[magnitude]*sin(theta)

so for this question use:
y = 7 * sin(45) = 4.94N

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4 0
3 years ago
What does the statement “10 m/s to the north” describe? A. time B. velocity
SVEN [57.7K]

Answer:

D. Position

Explanation:

10 m/s to the north means that an object is moving to the north and it doesn't matter neither the time nor the velocity.

This statement is just telling us the direction in which this object is moving.

8 0
3 years ago
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Suppose that you are headed toward a plateau 4040 m high. If the angle of elevation to the top of the plateau is 2020degrees°​,
Lelu [443]

Answer :

The distance is 109.89 m.

Explanation :

Given that,

Height = 40 m

Angle = 20°

We need to calculate the base of the​ plateau

Using formula of angle

\tan\thata=\dfrac{h}{x}

Where, h = height

x = base

\theta = angle

Put the value into the formula

\tan20^{\circ}=\dfrac{40}{x}

x=\dfrac{40}{tan20^{\circ}}

x =109.89\ m

Hence, The distance is 109.89 m.

3 0
3 years ago
A well-thrown ball is caught in a well-padded mitt. If the deceleration of the ball is 2.10×10^{4} 4 m/s^{2} 2 , and 1.85 ms (1
Paha777 [63]

Answer:

u = - 38.85 m/s^-1

Explanation:

given data:

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time = 1.85*10^{-3} s

final velocity = 0 m/s

from equation of motion we have following relation

v = u +at

0 =  u + 2.10*10^4 *1.85*10^{-3}

0 = u + (21 *1.85)

0 = u + 38.85

u = - 38.85 m/s^-1

negative sign indicate that the ball bounce in opposite directon

6 0
3 years ago
Consider the Uniform Circular Motion Gizmo configured as shown. Notice that, under the current settings, |a|=0.50m/s2. What chan
Eddi Din [679]

To increase the centripetal acceleration to 2.00 m/s^2, you can double the speed or decrease the radius by 1/4

Explanation:

An object is said to be in uniform circular motion when it is moving at a constant speed in a circular path.

The acceleration of an object in uniform circular motion is called centripetal acceleration, and it is given by

a=\frac{v^2}{r}

where

v is the speed of the object

r is the radius of the circular path

In the problem, the original centripetal acceleration is

a=0.50 m/s^2

We want to increase it by a factor of 4, i.e. to

a'=2.00 m/s^2

We notice that the centripetal acceleration is proportional to the square of the speed and inversely proportional to the radius, so we can do as follows:

- We can double the speed:

v' = 2v

This way, the new acceleration is

a'=\frac{(2v)^2}{r}=4(\frac{v^2}{r})=4a

so, 4 times the original acceleration

- We can decrease the radius to 1/4 of its original value:

r'=\frac{1}{4}r

So the new acceleration is

a'=\frac{v^2}{(r/4)}=4(\frac{v^2}{r})=4a

so, the acceleration has increased by a factor 4 again.

Learn more about centripetal acceleration:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

5 0
3 years ago
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