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Readme [11.4K]
3 years ago
14

What is the molarity of a 3.0-liter solution that contains 0.45 moles of solute?

Chemistry
1 answer:
MatroZZZ [7]3 years ago
7 0

Answer:

B

Explanation:

Moles = n/v where n is the moles of solute and v being the liters of solution.

We can put in the information provided to find the molarity.

Moles = .45/3.0 = .15

So we now know that the molarity of that solution is .15

i just found on web hope this helps

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What will happen to the pH of a solution when the [H+] is increased?
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Answer:

decreases

Explanation:

the more conc of H ions increases the more it becomes acidic so the pH goes down

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If a plant produces 9.31 mol of C6H12O6, how many moles of H2O are needed?
Mashutka [201]

The complete balanced chemical equation for photosynthesis in plants is:

6CO₂ + 6H₂O ----> C₆H₁₂O₆ + 6O₂

Based on the balanced equation the molar ratio between H₂O and C₆H₁₂O₆ is 6:1

This means that 6 moles of H₂O is need for every 1 mole of C₆H₁₂O₆

9.31 mol of C₆H₁₂O₆ x (6 moles of H₂O / 1 mole of C₆H₁₂O₆) = 55.86 moles of H₂O

Thus the moles of H₂O need is 55.86 .


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3 years ago
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If two protons and two neutrons are added to the nucleus of a carbon atom, what nucleus does it become?
Shkiper50 [21]
If two protons are added to carbon, the chemical identity changes to oxygen, which is two spaces over horizontally on the periodic table. The number of protons is what we call the atomic number (Z), and this is what defines the identity of an element. Since we also added two neutrons, this is simply oxygen, or oxygen-16, the most abundant isotope of oxygen.
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The competition between the U.S. and the Soviet Union to get satellites and humans into space was known as the:
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Answer: It was known as the SPACE RACE.

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7 0
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Find the pHpH of a solution prepared from 1.0 LL of a 0.15 MM solution of Ba(OH)2Ba(OH)2 and excess Zn(OH)2(s)Zn(OH)2(s). The Ks
charle [14.2K]

Answer:

pH  = 13.09

Explanation:

Zn(OH)2 --> Zn+2 + 2OH-   Ksp = 3X10^-15

Zn+2 + 4OH-   --> Zn(OH)4-2   Kf = 2X10^15

K = Ksp X Kf

  = 3*2*10^-15 * 10^15

  = 6

Concentration of OH⁻ = 2[Ba(OH)₂] = 2 * 0.15 = 3 M

                Zn(OH)₂ + 2OH⁻(aq)  --> Zn(OH)₄²⁻(aq)

Initial:           0             0.3                      0

Change:                      -2x                     +x

Equilibrium:               0.3 - 2x                 x

K = Zn(OH)₄²⁻/[OH⁻]²

6 = x/(0.3 - 2x)²  

6 = x/(0.3 -2x)(0.3 -2x)

6(0.09 -1.2x + 4x²) = x

0.54 - 7.2x + 24x² = x

24x² - 8.2x + 0.54 = 0

Upon solving as quadratic equation, we obtain;

x = 0.089

Therefore,

Concentration of (OH⁻) = 0.3 - 2x

                                    = 0.3 -(2*0.089)

                                  = 0.122

pOH = -log[OH⁻]

         = -log 0.122

          = 0.91

pH = 14-0.91

     = 13.09

4 0
3 years ago
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