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3 years ago

If a plant produces 9.31 mol of C6H12O6, how many moles of H2O are needed?

Chemistry

2 answers:

Mashutka [201]3 years ago

5 0

The complete balanced chemical equation for photosynthesis in plants is:

6CO₂ + 6H₂O ----> C₆H₁₂O₆ + 6O₂

Based on the balanced equation the molar ratio between H₂O and C₆H₁₂O₆ is 6:1

This means that 6 moles of H₂O is need for every 1 mole of C₆H₁₂O₆

9.31 mol of C₆H₁₂O₆ x (6 moles of H₂O / 1 mole of C₆H₁₂O₆) = 55.86 moles of H₂O

Thus the moles of H₂O need is 55.86 .

Sladkaya [172]3 years ago

4 0

Answer;

55.86 moles

Explanation;

Six molecule of H2O is needed for every molecule of C6H12O6 to be produced.

This means the ratio of H2O: C6H12O6 is 6:1

Let H2O mole= X

Therefore...

X/9.31 = 6/1

X= 6 x 9.31

X = 55.86 moles

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If you had 6 moles of CaCl2 and 5 moles of Na3PO4, which of these would be the limiting and excess reactant

faltersainse [42]

Answer:

Na3PO4 is excess reactant, CaCl2 is limiting reactant.

Explanation:

3CaCl2 + 2Na3PO4 ---> Ca3(PO4)2 + 6NaCl

from reaction : 3 mol 2 mol

given: 6 mol 5 mol (X)

X = (6*2)/3 = 4 mol Na3PO4

For 6 mol CaCl2 we need 4 mol Na3PO4, but we have 5 mol Na3PO4,

Na3PO4 is excess reactant, so CaCl2 is limiting reactant.

8 0

3 years ago

Which of the following is not equal to 485 L?

ELEN [110]

Answer:

$4.85 * 10^4\ mL$

Explanation:

Given

485 L

Required

Determine the measurement not equal to 485L

$0.485\ kL$

From standard unit of conversion;

1 KL = 1000 L

Multiply both sides by 485

$485 * 1 KL = 485 * 1000 L$

$485KL = 485000L$

Divide both sides by 1000

$\frac{485KL}{1000} = \frac{485000L}{1000}$

$0.485KL = 485L$ ---- This is equivalent

---------------------------------------------------------------------------------------------

$4.85 * 10^4\ mL$

From standard unit of conversion;

1000 mL = 1 L

Multiply both sides by 485

$485 * 1000 mL = 1 L * 485$

$485000\ mL = 485\ L$

Convert to standard form

$4.85 * 10^5\ mL = 485\ L$

Hence; $4.85 * 10^4\ mL$ is not equivalent to 485L

---------------------------------------------------------------------------------------------

$48500 \ cL$

From standard unit of conversion;

100 cL = 1 L

Multiply both sides by 485

$485 * 100 cL = 1 L * 485$

$48500\ cL = 485\ L$

Convert to standard form

$4.85 * 10^4\ cL = 485\ L$ ---- This is equivalent

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$4.85 * 10^8 \$ μL

From standard unit of conversion;

1000000 μL = 1 L

Multiply both sides by 485

$485 * 1000000uL = 1 L * 485$

$485000000uL = 485\ L$

Convert to standard form

$4.85 * 10^8\ uL = 485\ L$ ---- This is equivalent

From the list of given options;

$4.85 * 10^4\ mL$ is not equivalent to 485L

4 0

3 years ago

What is the mass of 4 moles of almunium atom

lana [24]

Answer:

108 grams

Explanation:

5 0

3 years ago

How many calories of heat are necessary to raise the temperature of 319.5 g of water from 35.7 °C

rjkz [21]

20600Cal

Explanation:

Given parameters:

Mass of water = 319.5g

Initial temperature = 35.7°C

Final temperature = 100°C

Unknown:

Calories needed to heat the water = ?

Solution:

The calories is the amount of heat added to the water. This can be determined using;

H = m c Ф

c = specific heat capacity of water = 4.186J/g°C

H is the amount of heat

Ф is the change in temperature

H = m c (Ф₂ - Ф₁)

H = 319.5 x 4.186 x (100 - 35.7) = 85996.56J

Now;

1kilocalorie = 4184J

85996.56J to kCal; $\frac{85996.56}{4184}$ = 20.6kCal = 20600Cal

learn more:

Specific heat brainly.com/question/3032746

#learnwithBrainly

6 0

3 years ago

Neutral atoms contain equal numbers of A protons and electrons. B protons and neutrons. C electrons and neutrons. D protons, ele

Verdich [7]

Answer:

For 1: The correct answer is Option A.

For 2: The correct answer is Option B.

For 3: The correct answer is Option C.

Explanation:

For 1:

Atomic number is defined as the number of electrons or number of protons that are present in a neutral atom. It is represented as Z.

Z = Atomic number = Number of electrons = Number of protons

Mass number is defined as the sum of number of protons and number of neutrons present in an atom. It is represented as A.

A = Mass number = Number of protons + Number of neutrons

Hence, the correct answer is Option A.

For 2:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

We are given:

An isotopic representation of beryllium atom: $_4^9\textrm{Be}$

Thus, the number '4' represents the atomic number of beryllium, number '9' represents the mass number of beryllium atom.

Hence, the correct answer is Option B.

For 3:

In CO compound:

Mass of oxygen = 16 g

Mass of carbon = 12 g

In $CO_2$ compound:

Mass of oxygen = 32 g

Mass of carbon = 12 g

Thus, the ratio of mass of oxygen in $CO_2$ and CO is:

$CO_2:CO=32:16=2:1$

Hence, the correct answer is Option C.

3 0

3 years ago