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bekas [8.4K]
4 years ago
7

The climate of a place also depends upon the amount of water in the air. How do the rising temperatures around Earth affect the

amount of water in the air? A) The water in the air evaporates because the temperature of air is rising. B) There is more water in the air because the rate of evaporation increases. C) The water in the air decreases because the water on Earth starts evaporating. D) There is less water in the air because the evaporated water falls down as rain.
Chemistry
1 answer:
kodGreya [7K]4 years ago
5 0

Answer:

B) There is more water in the air because the rate of evaporation increases

Explanation:

As the temperatures rise across the globe, the rate of evaporation also increases, resulting in more water in the air. The reason for the increased evaporation is that the ice sheets and glaciers are melting, thus there's more liquid water. The more liquid water there is, the more evaporation there will be. As the evaporation increases, there will be an increase in the formation of clouds, thus there will be more precipitation around the world, gradually leading to warmer and wetter climate.

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How many grams of Ag2S2O3 form
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Taking into account the reaction stoichiometry, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgBr + Na₂S₂O₃ → Ag₂S₂O₃ + 2 NaBr

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • AgBr: 2 moles
  • Na₂S₂O₃: 1 mole
  • Ag₂S₂O₃: 1 mole
  • NaBr: 2 moles

The molar mass of the compounds is:

  • AgBr: 187.77 g/mole
  • Na₂S₂O₃: 158 g/mole
  • Ag₂S₂O₃: 327.74 g/mole
  • NaBr: 102.9 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • AgBr: 2 moles ×187.77 g/mole= 375.54 grams
  • Na₂S₂O₃: 1 mole ×158 g/mole= 158 grams
  • Ag₂S₂O₃: 1 mole ×327.74 g/mole= 327.74 grams
  • NaBr: 2 moles ×102.9 g/mole= 205.8 grams

<h3>Mass of Ag₂S₂O₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 375.54 grams of AgBr form 327.74 grams of Ag₂S₂O₃, 125 grams of AgBr form how much mass of Ag₂S₂O₃?

mass of Ag_{2} S_{2} O_{3} =\frac{125 grams of AgBrx327.74 grams of Ag_{2} S_{2} O_{3}}{375.54 grams of AgBr}

<u><em>mass of Ag₂S₂O₃= 109.09 grams</em></u>

Then, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

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4 0
2 years ago
What is always true of an object with a lot of mass?
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Answer:

A) It contains a lot of matter.

8 0
4 years ago
A piece of wood near a fire is at 23°c. it gains 1,160 joules of heat from the fire and reaches a temperature of 42°c. the speci
Alex73 [517]

The mass of the piece of wood is 35.58 g.

Joule = M × T × C

Where, M = mass

T = change in temperature(42C-23C=19 C)

C = specific heat capacity = 1.716 joules/gram

Substituting the values in the equation,

1160 = M × 19 × 1.716

M = 1160/32.604 = 35.58 g

Therefore, the mass of the piece of wood = 35.58 g

<h3>What is meant by specific heat capacity?</h3>

A material's specific heat capacity, which is defined as its heat capacity divided by its mass, determines how much energy is required to increase a gram's temperature by one degree Celsius (or one Kelvin)

<h3>What is mass?</h3>

Mass is the quantity of matter in a physical body.

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7 0
1 year ago
How many atoms of oxygen are present in 7.51 grams of<br> glycine with formula C₂H5O2N?
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1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

However, the number of moles of oxygen in glycine can be calculated using the following expression:

Molar mass of C₂H5O2N = 75.07g/mol

Mass of oxygen in glycine = 32g/mol

Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine

Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles

Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms

Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.

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2 years ago
Calculate the number of protons, neutrons and electrons in Copper
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  1. neutrons=35
  2. protons=29
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3 years ago
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