Question

The molar mass of carbon dioxide (CO2) is 44.01 g/mol. The molar mass of water (H2O) is 18.01 g/mol. A reaction uses 528 g of CO2. How many moles of water are used in this reaction?

Answer 1

CO₂  +  H₂O  ------->  H₂CO₃

moles of CO₂ = $\frac{MASS of Carbon}{ MOLAR MASS}$
              
                       = $\frac{528 g}{44.01 g / mol}$
 
                       =  11.997 mol

mole ratio of  CO₂  :  H₂O  =   1  :  1
           
            ∴ moles of H₂O  =  (`11.997 mol )  *  1
                                       =  11.997 mol
                                       ≈  12  mol