Time taken by proton to complete one complete circular orbit= 7.28 x 10⁻⁸ s
Explanation:
For proton, the centripetal force required for circular motion is provided by the magnetic force,
so Fm= Fc
q v B = m v²/r
m= mass of charged particle
v= velocity
B =magnetic field
q= charge
r= radius of circular path
v= q B r/m
now v= r ω
ω= angular velocity
ω r = q B r /m
ω=q B /m
now ω= 2π/T where T =time period
so 2π/T=q B/m
T= 2 πm/q B
T= 2π (1.67 x 10⁻²⁷)/ [( 1.6 x 10⁻¹⁹)* (0.9)]
T= 7.28 x 10⁻⁸ s
The shades are very different
Answer:
A)
B)
C)
Explanation:
Given that a pendulum is suspended by a shaft with a very light thin rod.
Followed by the given information: m = 100 g, I = 0.5 m, g = 9.8 m / s²
We can determine the answer to these questions using angular kinematics.
Angular kinematics is just derived from linear kinematics but in different symbols, and expressions.
Here are the formulas for angular kinematics:
- θ = ωt
- ∆w =
- L [Angular momentum] = mvr [mass × velocity × radius]
A) What is the minimum speed required for the pendulum to traverse the complete circle?
We can use the formula v = √gL derived from
B) The same question if the pendulum is suspended with a wire?
C) What is the ratio of the two calculated speeds?
We take the derivative of Ohm's law with respect to time: V = IR
Using the product rule:
dV/dt = I(dR/dt) + R(dI/dt)
We are given that voltage is decreasing at 0.03 V/s, resistance is increasing at 0.04 ohm/s, resistance itself is 200 ohms, and current is 0.04 A. Substituting:
-0.03 V/s = (0.04 A)(0.04 ohm/s) + (200 ohms)(dI/dt)
dI/dt = -0.000158 = -1.58 x 10^-4 A/s
Acceleration = (change in speed)/(time for the change)
Change in speed = (end speed) - (start speed)
Change in speed = (10 m/s) - (20 m/s) = -10 m/s
Time for the change = 5.00 seconds
Acceleration = (-10 m/s) / (5 sec)
<em>Acceleration = -2 m/s²</em>
That's choice-A .
