Orient the semi-circle arc such that it is symmetric with respect to the y-axis. Now, by symmetry, the electric field in the x-direction cancels to zero. So the only thing of interest is the electric field in the y-direction.
dEy=kp/r^2*sin(a) where k is coulombs constant p is the charge density r is the radius of the arc and a is the angular position of each point on the arc (ranging from 0 to pi. Integrating this renders 2kq/(pi*r^3). Where k is 9*10^9, q is 9.8 uC r is .093 m
I answeared your question can you answear my question pleas
Answer:
The statements A and D are true
The statements B and C are false
Explanation:
The force between charges can be explained by the Coulomb's Law.
According to Coulomb:
1 - Like charges always repel each other
2- Unlike or opposite charges always attrack each other
3- Force between 2 charges is given by:

where F is the force between 2 charges and r is the distance between 2 charges.
We can see that Force F is inversely proportional to the distance r
Which means that when F increase, r decreases and when F decreases, r increases
Well the diagram would look like the water cycle I think
Answer
given,
flow from the artery = 3.5 x 10⁻⁶ m³/s
Radius of artery = 5.80 x 10⁻³m
area = π R²
= π x (5.8 x 10⁻³)²
= 1.06 x 10⁻⁴ m²


v = 0.033 m/s
b) new velocity of flow
Radius = R' = R/4
A V = A' V'
R² V = R'² V'
R^2 V = (\dfrac{R}{4})^2 V'
V' = 16 V
V' = 16 x 0.033
V' =0.528 m/s