Number 29 plz help physics
1 answer:
Answer:
a. E = 900000 J = 900 KJ
b. ΔT = 8.18 °C
c. Cost = $ 7.2
Explanation:
a.
The energy can be given by:
where,
E = Energy = ?
P = Power = 500 W
t = time = (0.5 h)(3600 s/1 h) = 1800 s
Therefore,
<u>E = 900000 J = 900 KJ</u>
b.
The change in temperature of room air is given by the following formula:
(since 50% of energy is used to heat air)
where,
m = mass of air = 50 kg
C = specific heat of air = 1.1 KJ/kg.°C
ΔT = Change in temperature of air = ?
Therefore,
<u>ΔT = 8.18 °C</u>
c.
First, we will calculate the total energy consumed:
Now, for the cost:
<u>Cost = $ 7.2</u>
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Answer:
51.96 m/s^-1
Explanation:
a) see the attachment
b) As we know the velocity of the projectile has two component, horizontal velocity v_ox. and vertical velocity v_oy as shown in the figure. At the highest point of the trajectory, the projectile has only horizontal velocity and vertical velocity is zero. Therefore at the highest point of the trajectory, the velocity of the projectile will be
v_ox=v_o*cosФ
=60*cos (30)
= 51.96 m/s^-1
Answer:
a) E = 0
b)
Explanation:
The electric field for all points outside the spherical shell is given as follows;
a)
From which we have;
E = 0/A = 0
E = 0
b)
By Gauss theorem, we have;
Therefore, we get;
The electrical field outside the spherical shell
Therefore, we have;