Answer:
Yes, I'm pretty sure it is. That's why I don't click on it!
<u>Answer:</u> The velocity of released alpha particle is 
<u>Explanation:</u>
According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.
For a system:

where,
= Initial mass and velocity
= Final mass and velocity
We are given:

Putting values in above equation, we get:

Hence, the velocity of released alpha particle is 
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
For convenience write RC=D and solve the ODE dV/dt=-V/D which gives
<span>V=Ae^(-t/D) by separating the variables. </span>
<span>When t=0, V=10 and this gives A=10, </span>
<span>when t=2, V=1 giving 1=10e^(-2/D) and you can find D by taking lns of </span>
<span>each side. D=RC, so R=D/C </span>
<span>You should get 2.90X10^5 ohms</span>
Answer:
(F)reaction = - 75 N
where, negative sign shows opposite direction.
Explanation:
This question can be answered using Newton's third law of motion. The Newton's Third Law of Motion states that for every action force there is an equal but opposite reaction force.
(F)action = - (F)reaction
Hence, in our scenario if we consider the 75 Newton force applied on the wall to be the action force then the reaction force of the wall must be equal to it in opposite direction. Therefore, the reaction push of the wall must be equal to 75 N.
<u>(F)reaction = - 75 N</u>
<u>where, negative sign shows opposite direction.</u>
I believe that the answer is C. Hope this Helps:)))