Find an equation of the plane that passes through the point P0 = (6, 3, 2) and is parallel to the xy-plane. g
1 answer:
The <em>xy</em>-plane has a normal vector of 〈0, 0, 1〉, and any plane parallel to it will have the same normal vector.
Then the equation of the plane through (6, 3, 2) that is parallel to the <em>xy</em>-plane has equation
〈<em>x</em> - 6, <em>y</em> - 3, <em>z</em> - 2〉 • 〈0, 0, 1〉 = 0
==> <em>z</em> - 2 = 0
==> <em>z</em> = 2
You might be interested in
Answer:
-7
Step-by-step explanation:
The full coordinate is (-7,3) the dot is on the line between -6 and -8
Answer:
2025!!
Step-by-step explanation:
The answer is D.
Y=2x Y=x(2)-3
2=2(1) 2=3(2)-3
2=2 2=6-3
2=2
Answer:
12+36p
Step-by-step explanation:
First distribute the 2 to binomial then the 6.
6(2+6p)
12+36p
Minuim i think because maximum is not right