Find an equation of the plane that passes through the point P0 = (6, 3, 2) and is parallel to the xy-plane. g

Mathematics

1 answer:

Nutka1998 [239]3 years ago

3 0

The xy-plane has a normal vector of 〈0, 0, 1〉, and any plane parallel to it will have the same normal vector.

Then the equation of the plane through (6, 3, 2) that is parallel to the xy-plane has equation

〈x - 6, y - 3, z - 2〉 • 〈0, 0, 1〉 = 0

==> z - 2 = 0

==> z = 2

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a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

See the image in the attachment for the referred diagram.

The two triangles, triangle AEC and triangle BDC are similar triangles.
Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

This implies that: