During the "U" part of the turn, the car would follow an approximately circular path, and if it's moving at a constant speed, it would have to accelerate toward the center of the circle in order to change its direction.
In 1991 four English teenagers built an eletric car that could attain a speed of 30.0m/s. Suppose it takes 8.0s for this car to
2 answers:
Answer:
Acceleration of the car,
Explanation:
It is given that,
Initial speed of the car, u = 18 m/s
Final speed of the car, v = 30 m/s
Time taken, t = 8 s
We need to find the acceleration of the car. Let it is given by a. It can be calculated using the first equation of motion.
Where
a is the acceleration of the car.
So, the magnitude of the car's acceleration is . Hence, this is the required solution.
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Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :
B is magnetic field
So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.