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puteri [66]
4 years ago
10

Can fatigue seriously impair driving ability

Physics
2 answers:
valina [46]4 years ago
8 0
Yes. 
Fatigue is a exhaustion of muscles and general exhaustion. Driving when tired and fatigued is worse than driving drunk.
omeli [17]4 years ago
6 0
Fatigue is the number one cause of accidents.
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Which list of elements contains only metals?
fredd [130]
C. those are all metals.
6 0
4 years ago
Read 2 more answers
A box experiencing a gravitational force of 600 N. is being pulled to the right with a force of 250 N. 825 N. frictional force a
lidiya [134]

Answer:A

Explanation:

Explanation:

Given that,

Gravitational force = 600 N

Frictional force = 25 N

Pulled by the Force = 250 N

We know that,

The gravitational force in downward and normal force act in upward. the frictional force in left side and the box pulled by the force to the right side.

The balance equation is along y-axis

The box will not move in y-axis therefore, the net force in the y-axis will be zero.

Hence, The net force in the y-direction will be zero.

8 0
3 years ago
A projectile is launched horizontally from a raised platform. If air resistance is ignored, then as the projectile falls to the
aliya0001 [1]

<h2>The option ( b ) is appropriate answer </h2>

Explanation:

When a projectile is projected from height horizontally . The only force acting upon it is the downwards gravitational force of attraction due to earth .

Due to this force its vertical component of velocity , which is in the downward direction will be increased .

As there is no force horizontally , the horizontal  velocity of throw will remain constant .

Thus ( b ) option is the correct option .

6 0
3 years ago
Two 2.0-cm-diameter insulating spheres have a 6.60 cm space between them. One sphere is charged to + 76.0 nC , the other to - 30
e-lub [12.9K]

Answer:

5.2\times 10^5N/C

Explanation:

Since the two charged bodies are symmetric, we can calculate the electric field taking both of them as point charges.

This can be easily seen if we use Gauss's law, \int{E} \, dA=\frac{Q_{enclosed}}{\epsilon_o}

We take a larger sphere of radius, say r, as the Gaussian surface. Then the electric field due to the charged sphere at a distance r from it's center is given by,

E=\frac{1}{4\pi r^2} \frac{Q_{enclosed}}{\epsilon_o}

which is the same as that of a point charge.

In our problem the charges being of opposite signs, the electric field will add up. Therefore,

E_{total}=\frac{1}{4\pi\epsilon_o}\frac{q_1+q_2}{r^2}= (9\times10^9) \frac{(76+30)\times10^{-9}}{((1+3.3)\times10^{-2})^2}N/C =5.2\times10^5N/C

where, r = distance between the center of one sphere to the midpoint (between the 2 spheres)

8 0
3 years ago
A car is traveling at a velocity of 20 m/s. the driver applies the brakes, and the car slows with an acceleration of a = -4.0 me
sasho [114]
   
\displaystyle\\&#10;V = a\times t\\\\&#10;t= \frac{V}{a} =   \frac{20}{4} = 5~s\\\\&#10;D =  \frac{a\times t^2}{2} =  \frac{4\times 5^2}{2} = 2 \times 25 = 50~m



3 0
3 years ago
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