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UNO [17]
4 years ago
8

Find the impulse a 1500 kg car experiences slowing down from 40m/s to 10m/s?

Physics
1 answer:
Kitty [74]4 years ago
6 0

Answer: - 45000 N.s

Explanation: Impulse is equal to the change in momentum

J = Δp

To solve for impulse we calculate the change in momentum

Δp = m ( Δv)

     = 1500 kg ( 10 m/s - 40 m/s)

     = - 45000 N.s

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3 0
3 years ago
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A 2000 Hz siren and a civil defense official are both at rest with respect to the ground. What frequency does the official hear
astra-53 [7]

Answer:

a)f_1 = 2070.6 Hz

b)f_2 = 1929.4 Hz

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Apparent frequency of the siren is given as

f = \frac{v_{rel}}{\lambda}

as we know that the wavelength will remain the same as it is having originally

sowe know

\lambda = \frac{340}{2000}

\lambda = 0.17 m

a) Now when wind is blowing from source to official

so we have

v_{rel} = 340 + 12 = 352 m/s

so we have

f_1 = \frac{352}{0.17}

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4 0
4 years ago
A 5 kg
kotykmax [81]

Answer:

<em>The object-Earth system is open</em>

F_n=ma=5\ (7.2)=36\ N

Explanation:

<u>Accelerated Motion </u>

When an object is released in free air (with no other forces than the gravity), it describes a free-fall motion and the formulas include the acceleration of gravity as part of the calculations. But when there is another external force, then the acceleration is not the gravity, but the result of the net force exerted on the mass of the object.

By definition, an open system includes the exchange of energy from and to the surroundings, that is why all systems surrounding our planet are considered as open systems. In our case, the object is interacting with the planet's gravity and there is some other external force, which will be computed later. The object-Earth system is open.

If the object starts from rest, its initial speed is zero, and

v_f=a\ t

where a is the acceleration and t is the time. The distance traveled is given by :

\displaystyle y=\frac{a\ t^2}{2}

From the two above equations, we find that:

v_f^2=2ay

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\displaystyle a=\frac{v_f^2}{2y}

\displaystyle a=\frac{12^2}{2\ (10)}

a=7.2\ m/s^2

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F_n=ma=5\ (7.2)=36\ N

The object's weight is

W=5\ (9.8)=49 N

This means there is some external force acting upwards delaying the object's fall of a magnitude of

F_e=49-36=13\ N

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The molecules making up object collide with the molecules of the other and some of the kinetic energy from a warmer object is transferred to the cooler one.

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