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Ghella [55]
3 years ago
7

A pole vaulter takes 1.3 seconds to fall from peak height to the landing mat. What is his vertical velocity at contact with the

mat?
Physics
1 answer:
julia-pushkina [17]3 years ago
6 0

12.75 \frac{m}{s}

Assuming vertical acceleration of 9.81 \frac{m}{s^2}, the speed after x seconds of falling is 9.81x \to 9.81(1.3) = 12.75

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3 years ago
Assume your mass is 60 kg. The acceleration due to gravity is 9.8 m/s 2 . How much work against gravity do you do when you climb
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W=1705.2 J

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Now by putting the values

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