The correct answer is 2 N/cm, I take k12 and that was the correct answer
d(t) = 1.1t² + t + 1
The constant speed required to cover the same distance between t = 3 to t = 5 is the same as the average speed over that same time interval. It is given by:
v = Δx/Δt
v = average speed, Δx = change in distance, Δt = elapsed time
Given values:
Δx = d(5) - d(3) = 19.6ft
Δt = 5s - 3s = 2s
Plug in and solve for v:
v = 19.6/2
v = 9.8ft/s
Answer:
0.316 m.
Explanation:
Frequency, f = 0.19 Hz
Using curcular motion equation,
ω = 2π*f
= 1.19 rad/s
Maximum acceleration, a(max) = 2.3 % *9.8m/s^2
= 0.023 * 9.8
= 0.225 m/s^2
In simple harmomic motion,
a(max) = A*ω^2
Where,
A = amplitude
= 0.225/1.19^2
= 0.158 m
2A = 0.316 m.
Answer :
The number of vacancies (per meter cube) = 5.778 × 10^22/m^3.
Explanation:
Given,
Atomic mass of silver = 107.87 g/mol
Density of silver = 10.35 g/cm^3
Converting to g/m^3,
= 10.35 g/cm^3 × 10^6cm^3/m^3
= 10.35 × 10^6 g/m^3
Avogadro's number = 6.022 × 10^23 atoms/mol
Fraction of lattice sites that are vacant in silver = 1 × 10^-6
Nag = (Na * Da)/Aag
Where,
Nag = Total number of lattice sites in Ag
Na = Avogadro's number
Da = Density of silver
Aag = Atomic weight of silver
= (6.022 × 10^23 × (10.35 × 10^6)/107.87
= 5.778 × 10^28 atoms/m^3
The number of vacancies (per meter cube) = 5.778 × 10^28 × 1 × 10^-6
= 5.778 × 10^22/m^3.