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uranmaximum [27]
3 years ago
15

Match the correct theorem or postulate with the correct statement.

Mathematics
1 answer:
Roman55 [17]3 years ago
4 0

1. Unique line postulate

Statement: Through any two points, there is exactly one line.

2. Line intersection postulate

Statement: If two lines intersect, then their intersection is exactly one point.

3. Segment addition postulate

Statement: If A, B and C are collinear and B is between A and C, then AB + BC = AC

4. Angle Addition postulate

Statement: If R is in interior of \angle PQS, then m \angle PQR + m \angle RQS = m \angle PQS.

5. Linear pair theorem

Statement: If two angles form a linear pair, then the angles are supplementary.

6. Congruent Complements theorem

Statement: If two angles are complementary to the same angle, then the angles are congruent.

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__________________________________________
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Answer:

3.3 x 10⁻⁴

Step-by-step explanation:

Given expression:

           \frac{2.64 x 10^{-3} }{8.0 x 10^{0} }

 To solve this problem;

    10°   = 1

So;

             \frac{2.64 x 10^{-3} }{8.0}

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4 0
3 years ago
Rene is going to the lake to visit some friends. If the lake is 60 miles away and Rene is driving at 40 miles per hour the entir
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It will take her an hour and a hlaf

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3 years ago
Find the value of X
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7 0
2 years ago
Read 2 more answers
Patricia and Joe Payne are divorced. The divorce settlement stipulated that Joe pay $485 a month for their daughter Suzanne unti
zhuklara [117]
\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array} &
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &
\begin{array}{llll}
485\cdot 12\\
\underline{5280}
\end{array}\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{a year, thus once}
\end{array}\to &1\\

t=years\to &4
\end{cases}
\\\\\\


\bf A=5280\left[ \cfrac{\left( 1+\frac{0.06}{1} \right)^{1\cdot  4}-1}{\frac{0.06}{1}} \right]

Joe is making $485 payments monthly, but the amount gets interest on a yearly basis, not monthly, so the amount that yields interest is 485*12

also, keep in mind, we're assuming is compound interest, as opposed to simple interest
3 0
3 years ago
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