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Paraphin [41]
4 years ago
13

There are 48 students in a school play. The ratio of boys to girls is 5:7. How many boys are in the school play? Explain how you

found your answer
Mathematics
2 answers:
mr Goodwill [35]4 years ago
7 0
Boys:  x
gilrs:   y

From the text of the task:

\left \{ {{\frac{x}{y}=\frac{5}{7}} \atop {x+y=48 \rightarrow x=48-y}} \right.

Replacing x:

\frac{48-y}{y}=\frac{5}{7}\\
\\
7(48-y)=5y\\
\\
336-7y=5y\\
\\
12y=336\\
\\
y=\frac{336}{12}=28

So there are 28 girs and 20 boys
fomenos4 years ago
5 0
Did you say that the ratio of boys to girls is 5 to 7 ?

Well, then we know that 5 'groups' in the cast are boys, and 7 'groups' are girls.
So all together, there are 12 'groups' of students in the play, although we don't know
how many a 'group' is.

But wait a second.  You said there are 48 all together.  So each 'group' must be
48/12 = 4 students.

5 'groups' of boys = 20 boys
7 'groups' of girls = 28 girls

Check:

-- The ratio of 20 to 28 is 5 to 7 .  OK

-- 20 + 28 = 48 all together. OK

It all checks out.
yay
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\dfrac{7}{12}x-\dfrac{1}{3}=\dfrac{1}{2}+\dfrac{3}{8}\\\\LCM(12,\ 3,\ 2,\ 8)=24\\\\\text{multiply both sides by 24}\\\\24\cdot\dfrac{7}{12}x-12\cdot\dfrac{1}{3}=12\cdot\dfrac{1}{2}+24\cdot\dfrac{3}{8}\\\\2\cdot7x-8=12+3\cdot3\\\\14x-8=12+9\\\\14x-8=21\qquad|\text{add 8 to both sides}\\\\14x=29\qquad|\text{divide both sides by 14}\\\\x=\dfrac{29}{14}

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3 years ago
6.833 + 3.594 + 1.369 nearest whole number
Naya [18.7K]

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B: T = ½R

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