Answer:
larry is incorrect because the number 2 is not a composite number, although numbers 12, 22, 32, 42, 52, 62, 72, 82, and 92 are composite, 2 isn't
Answer:
-4 and 4
Step-by-step explanation:
You count between the zeros as when you jump on a number line or just don't count the zero
-4, -3, -2 ,-1, 0, 1, 2 ,3, 4
Hope this helps
Answer:
2x² + 6x + 20
Step-by-step explanation:
See the picture
Answer:
It's 8
Step-by-step explanation:
![16 ^{ \frac{3}{4} } = \sqrt[4]{16 ^{3} } = \sqrt[4]{2 ^{4 \times 3} } = 2^{ \frac{12}{4} } = 2^{3} = 8](https://tex.z-dn.net/?f=%2016%20%5E%7B%20%5Cfrac%7B3%7D%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B16%20%5E%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B2%20%5E%7B4%20%5Ctimes%203%7D%20%7D%20%3D%202%5E%7B%20%5Cfrac%7B12%7D%7B4%7D%20%7D%20%20%20%3D%202%5E%7B3%7D%20%20%3D%208)
Answer:

Step-by-step explanation:
The formula for the accrued amount from compound interest is

1. Amount in account on 1 Jan 2015
(a) Data:
a = £23 517.60
r = 2.5 %
n = 1
t = 1 yr
(b) Calculations:
r = 0.025

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.
She must have had £23 944 in her account on 1 Jan 2015.
(2) Amount originally invested
(a) Data
A = £23 944.00

3. Summary
1 Jan 2014 P = £23 360.00
1 Jan 2015 A = 23 944.00
Withdrawal = <u> -1 000.00
</u>
P = 22 944.00
1 Jan 2016 A = £23 517.60