True
Because 9 is a odd number as of 1,3,5 are
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
8|x+2|-6=5|x+2|+3
|8x+16|-6=|5x+10|+3
I've been thinking... Is that | or (? Are you sure it's |?
Oh well, I'm continuing...
8x+16-6=5x+10+3
8x+10=5x+13
3x=3
x=1
Let x represent the amount to be added. The total amount of tin will be
15%·20 + 10%·x = 12%·(20+x)
(15%-12%)·20 = (12%-10%)·x
3%·20/2% = x
30 = x
30 pounds of 10% tin must be added to get a 12% mixture.