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levacccp [35]
3 years ago
9

99 is 90% of whatnumber?​

Mathematics
2 answers:
Eduardwww [97]3 years ago
8 0

Answer:

110

Step-by-step explanation:

Evgen [1.6K]3 years ago
7 0

Answer:

110

Step-by-step explanation:

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Find the sum of the geometric series.<br><br> a <br> b <br> c <br> d
Musya8 [376]

Answer:

B. 4\sqrt{3}-6

Step-by-step explanation:

We have,

The first term of the series, a=\sqrt{3}.

The common difference is given by, r=\frac{\frac{-3}{2}}{\sqrt{3}} i.e. r=\frac{-\sqrt{3}}{2}.

Since, the given series is an infinite series, then,

Sum of an infinite series = \frac{a}{1-r}

i.e. Sum the series = \frac{\sqrt{3}}{1+\frac{\sqrt{3}}{2}}

i.e. Sum the series = \frac{2\sqrt{3}}{2+\sqrt{3}}

i.e. Sum the series = \frac{2\sqrt{3}}{2+\sqrt{3}}\times \frac{2-\sqrt{3}}{2-\sqrt{3}}

i.e. Sum the series = \frac{2\sqrt{3}\times (2-\sqrt{3})}{4-3}

i.e. Sum the series = 4\sqrt{3}-6

Thus, the sum of the series is 4\sqrt{3}-6.

8 0
3 years ago
A car is traveling at 65 miles per hours. how many hours will it take to get to a town that is 130 miles away?
TiliK225 [7]
2 hours because 65 miles is = to one hour
130=65x2
130 miles is =to 2 hours
6 0
4 years ago
Two numbers that add to 4 and multiply to -21.
AnnyKZ [126]
I’m pretty sure this is right. if you add -3 and 7 you get 4 and if you multiply the two, you get -21. hope this helped!
3 0
3 years ago
Which expression is equivalent to log w (x2-6)4
natka813 [3]
Log w (x^2-6)^4

Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4

Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 =  log w + 4 log (x^2-6)

Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
7 0
4 years ago
Read 2 more answers
A​ boat's crew rowed 33kilometers​ downstream, with the​ current, in 3hours. The return trip​ upstream, against the​ current, co
algol [13]

Answer:

The crew rowing rate in still water = 7km/hr

The rate of the current = 4km/hr

Step-by-step explanation:

The distance rowed downstream with the current = 33km

Time taken to row downstream = 3hrs

The distance rowed upstream against the current = 33km

Time taken to row upstream = 11hrs

Let the crew's rowing rate in still water = Xkm/hr

Let the rate of current = Ykm/hr

For the downstream movement, we will have (X+Y). This is because the boat rowed with the current

For the upstream movement, we will have (X-Y). This is because the boat rowed against the current

Downstream Speed = distance /time

= 33/3

= 11km

Upstream speed = distance /time

= 33/11

= 3km

Hence X+Y = 11 and X-Y= 3

Add both equations. We have

X+Y+X-Y = 11 + 3

2X = 14

X= 14/2

X= 7

put X= 7 in any of the equations

7-Y= 3

Y= 7-3

Y= 4

Hence the crew rowing rate in still water = 7km/hr and the rate of the current = 4km/hr

6 0
3 years ago
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