An air pump does 5,600 J of work to launch a water bottle rocket into the air. If the air pump applies 150 N of force to the roc
2 answers:
Answer: 53 m
Explanation:
Work = Force × Displacement
W= F s cosΘ
Where, s is the displacement and F is the force. Θ is the angle between force and displacement
F cosθ is the component of force acting in the horizontal direction.
The air pump applies F = 150 N force at an angle Θ = 45°
W = 5600 J
⇒s = W/F cosθ
Thus, the horizontal distance the water bottle rocket travels is 53 m
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Answer:
The average net force on the truck is 375 Newtons.
Explanation:
Using Newton's 3rd equation of motion, we have :
×a×s
where, v = final velocity = 25 m/s
u = initial velocity = 20 m/s
a = acceleration
s = distance traveled = 300 m
Using these values in the above equation, we get acceleration = 0.375 m/
Using Newton's second law, we have:
F=m×a
where m = mass = 1000 kg
a= acceleration = 0.375 m/
Putting values we have F=375 N