Answer: B
Explanation: the teacher just told us the answer
But we do not know whether the force is pushing or pulling (the same direction (both forces are parallel) but: .........[ ]<-F-- or .......[ ]--F-->). I suppose the correct answer is B
Answer:
= 3,126 m / s
Explanation:
In a crash exercise the moment is conserved, for this a system formed by all the bodies before and after the crash is defined, so that the forces involved have been internalized.
the car has a mass of m = 1.50 kg a speed of v1 = 4.758 m / s and the mass of the train is M = 3.60 kg and its speed v2 = 2.45 m / s
Before the crash
p₀ = m v₁₀ + M v₂₀
After the inelastic shock
= m
+ M
p₀ = 
m v₀ + M v₂₀ = m
+ M
We cleared the end of the train
M
= m (v₁₀ - v1f) + M v₂₀
Let's calculate
3.60 v2f = 1.50 (2.15-4.75) + 3.60 2.45
= (-3.9 + 8.82) /3.60
= 1.36 m / s
As we can see, this speed is lower than the speed of the car, so the two bodies are joined
set speed must be
m v₁₀ + M v₂₀ = (m + M)
= (m v₁₀ + M v₂₀) / (m + M)
= (1.50 4.75 + 3.60 2.45) /(1.50 + 3.60)
= 3,126 m / s
<span>The centripetal force for such an arrangement can be found through the equation Fc = mv^2/r where m is the mass of the rotating object, v is that object's velocity, and r is the radius of rotation. In this case, we know that the maximum Fc that can be tolerated by the cord is 64N. Thus we set the equation up and solve for the value of v for which Fc = 64.
64 = 0.4*(v^2)/1
64/0.4 = 160 =
v^2
v = sqrt(160) = 12.65 m/s
At any speed faster than 12.65 m/s, the cord will break.</span>
Answer: force from sun to mars =
, force from mars to sun = 
Explanation: The force of attraction or repulsion between 2 object ( in this case the sun and mars ) in space is given by newton's law of gravitation which is given mathematically below as

where 
G = gravitational constant,
= mass of mars,
= mass of sun
the mars also exerts the same magnitude of force above on the sun but in the opposite direction, thus the force mars exerts on the sun is 