<span>It's another energy balance equation, though: energy to start with is the same as energy that you end with. Suppose that we start a distance r0 from the Earth and end a distance r1 from the Moon, then the energy balance gives:
1 v02 - G M / r0 - G m / (D - r0) = 1 v12 - G M / (D - r1) - G m / r1
...where m is the moon's mass.
One simple limit takes D ? ? and 1 v02 ? G M / r0 (the escape velocity equation), to yield:
1 v12 ? G M / r1
v1 ? ?( 2 G M / r1 ) = 2377 m/s.</span>
Answer:
orbital period increased by a factor of 2.83 unit
Explanation:
Given.
planet’s orbital period, T, and the planets mean distance from the sun, A, in astronomical units, AU
T²= A³
If A is increased by a factor of 2 , .
Then T will be increase with the factor of √2³ = 2.83
Answer:
0
-723.163841808 Wb
-350.282485876 Wb
Explanation:
= Permittivity of free space =
when r = 0.625 m the charges lie outside the sphere so q = 0
From Gauss law
The electric flux is 0
when r = 1.4
will be inside the sphere
The electric flux is -723.163841808 Wb
when r = 2.9 both charges lie inside the sphere
The electric flux is -350.282485876 Wb
<h2>
Angular acceleration is 80 rad/s²
</h2><h2>
Number of revolutions undergone is 1.02</h2>
Explanation:
We have equation of motion v = u + at
Initial angular velocity, u = 0 rad/s
Final angular velocity, v = 32 rad/s
Time, t = 0.40 s
Substituting
v = u + at
32 = 0 + a x 0.40
a = 80 rad/s²
Angular acceleration is 80 rad/s²
We have equation of motion s = ut + 0.5 at²
Initial angular velocity, u = 0 rad/s
Angular acceleration, a = 80 rad/s²
Time, t = 0.4 s
Substituting
s = ut + 0.5 at²
s = 0 x 0.4 + 0.5 x 80 x 0.4²
s = 6.4 rad
Angular displacement = 6.4 rad
Number of revolutions undergone is 1.02
Answer:
The force per unit length is
Explanation:
The current carrying by each wires = 2.85 A
The current in both wires flows in same direction.
The gap between the wires = 6.10 cm
Now we will use the below expression for the force per unit length. Moreover, before using the below formula we have to change the unit centimetre into meter. So, we just divide the centimetre with 100.