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3 years ago

8

To play his game, Charles must distribute 350 tokens, when there are 7 players. How many will he have to distribute for 11 playe

rs?

2 answers:

Black_prince [1.1K]3 years ago

5 0

Charles distributed 50 tokens per player so, he must distribute 550 tokens for eleven players.
350/7=50; 50*11=550.

Rzqust [24]3 years ago

4 0

First divide 350 with 7

350/7 = 50.

Each player gets 50 tokens.

Now there are 11 players.

Multiply 50 with 11

50 x 11 = 550

550 tokens are distributed for 11 players

hope this helps

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Abel saved 43 more nickels than dimes. After he spent 17 dimes he had twice as many nickels than dimes. How many coins did he ha

Alborosie

Answer:

180 coins

Explanation:

N = number of nickels (no nickels spent)

D = number of dimes initially saved

D' = number of dimes left after spending

1) N = D + 43

2) D' = D - 17

3) N = 2*D' = 2*(D - 17)

Set equations 1) and 3) equal to each other and solve for D:

D + 43 = 2*(D - 17)

D + 43 = 2*D - 34

D = 43 + 34 = 77

N = D + 43 = 77 + 43 = 120 nickels left

D' = D - 17 = 77 - 17 = 60 dimes left

Total coins left = 120 + 60 = 180 coins (I hope this is not too confusing for you)

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3 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

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3 years ago

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scoundrel [369]

Answer:

I believe it's C... Not sure though...

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3 years ago

How to do do trinomials in a easy way

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</span>Multiply the Inside<span> term
</span>Multiply the Last<span> terms
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Understand factoring.

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<span>Fill out the First terms.
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<span>Test which possibilities work with Outside and Inside multiplication.
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<span>Use simple factoring to make more complicated problems easier.
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<span>Look for trickier factors.
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<span>Solve problems with a number in front of the x^2.
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<span>Use substitution for higher-degree trinomials.
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Check for prime numbers.

Check to see if the trinomial is a perfect square.

<span>Check whether no solution exists.
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3 years ago