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Aleksandr-060686 [28]
2 years ago
9

Is d correct and did I do the process correctly

Chemistry
1 answer:
PIT_PIT [208]2 years ago
7 0

Answer:

1,500$

Explanation:

this would be the answer wouldn't it?

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How many molecules are there in 45.0 grams of CH ?
Sonbull [250]

Answer:

There are 1.8021 ⋅ 1024 molecules of CH4 in 48 grams of CH4. To answer this question, you must understand how to convert grams of a molecule into the number of molecules. To do this, you have to utilize the concepts of moles and molar mass. A mole is just a unit of measurement. Avogadro's number is equal to 6.022 ⋅1023 molecules/mole. i think please dont complain to me if its wrong im sorry

Explanation:

8 0
3 years ago
If m = 45g and V = 15ml, what is D in g/ml?​
ch4aika [34]

Answer:

3 g/mL

Explanation:

We know that the density of an object can be measured by dividing its mass (g) to its volume (mL).

Formula

D=m/v

Given data:

Mass= 45 g

Volume= 15 mL

Now we will put the values in formula:

D=45 g/ 15 mL= 3 g/mL

6 0
3 years ago
HELP !!!!!!! ASAP !!!!!!!!!!!!!!
Dmitry [639]
The color changes, heat change, smell change, are a few
4 0
3 years ago
Read 2 more answers
Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

3 0
3 years ago
Explain how the mass of a single atom in an element (in amu), the mass of one mole of that element, and Avogadro’s number are re
Eva8 [605]

Answer: For 1 mole of a single atom it is equal to its molar mass. And a single atom, 1 mole is equal to the Avogadro's Number.

Explanation: The relationship can be expressed through the following:

1 mole = molar mass of an atom/ compound

1 atom x 1 mole / 6.022x10^23  atoms

4 0
3 years ago
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