The vertical line can be (3,0) because that is where the x axis is starting at
Answer:
1. A
2. B
Step-by-step explanation:
1. Only option A creates that graph, the other options are either backwards or are on top of each other.
2. Because the two lines are parallel, and do not intersect at all, there will be 0 solutions.
Answer:
No, it can not be applied.
Step-by-step explanation:
f(x) = 1/x²
f(x) is a polynomial that is not continuous
As,
f(x) = 1/0 is undefines
Secondly, it is not differentiable (i.e. the derivative does not exists on the interval given)
Derivative of this function
f'(x) = (1)x^-2
= -2x^(-2-1)
= -2x^(-3)
= -2/x³
= -2/x³
f'(0) = -2/0 is undefined
Thus, mean value theorem can not be applied.
Answer:
Step-by-step explanation:
The leftmost line segment has a slope of -2 and (-1,-1) is a point on the line.
Equation: y = -2x-3
middle line segment has a slope of 0 and y-intercept of -2.
Equation: y = -2
The rightmost line segment has a slope of 1.5. (5,0) is a point on the line.
y = 1.5(x-5) = 1.5x-7.5