Question

A flashlight has a resistance of 2.4 . What voltage is applied by the batteries if the current in the circuit is

Answer 1

Answer : The voltage applied by the batteries is, 6.0 V

Solution : Given,

Resistance of flashlight = 2.4 ohm

Current in the circuit = 2.5 Ampere

Formula used :

$V=IR$

where,

V = applied voltage

I = current in the circuit

R = resistance of light

Now put all the given values in the above formula, we get

$V=(2.5A)\times (2.4ohm)=6volt=6V$

Therefore, the voltage applied by the batteries is, 6.0 V

Answer 2

Using V=IR, I is 2.5 and R is 2.4
 therefore answer is 2.4 multiply by 2.5 which is equal to 6v