Answer:
Matter in its solid state has the lowest amount of thermal energy (for that type of matter). Because solids have less thermal energy than liquids or gasses, the atoms in their solid state move very little.
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Answer:
The boiling point is somewhere between 56 and 151 °C
Explanation:
Hello,
In this case, it is possible to compute it via rigorous methods in phase equilibrium by using for example a cubic equation of state to model the vapor phase and a suitable excess Gibbs free energy model for the liquid phase, nonetheless, it is an arduous task. In such a way, since the information about both acetone's and nonane's pure boiling points is given as well as acetone's mole fraction, which points out it is about a binary liquid solution, one could make up the boiling point is somewhere between 56 and 151 °C precising that it should be closer to 151 °C as the mixture is 90% nonane and 10% acetone.
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Answer:
The answer to your question is: $ 35.6
Explanation:
C₆H₁₂N₂O₄Pt
Platinum = 52.5 %
Price = $1047 / troy ounce
cost of platinum = ? of 2 g
1 troy ounce = 480 grains
1 grain = 64.8 mg
Process
Get 52.5 % of 2 g
2 g ----------------- 100 %
x ----------------- 52.5%
x = (52.5 x 2) / 100
x = 1.05 g
1 g --------------------- 1000 mg
1.05 g ---------------- x
x = 1050 mg of Pt
1 grain ---------------- 64.8 mg
x --------------- 1050 mg
x = 16.2 grains
480 grains ---------------- 1 troy ounce
16.2 grains ---------------- x
x = (16.2 x 1) / 480
x = 0.034 troy ounce
$ 1047 ------------------ 1 troy ounce
x ------------------- 0.034
x = (0,034 x 1047) / 1
x = $ 35.6
Question:
A chemistry student needs of 10 g isopropenylbenzene for an experiment. He has available 120 g of a 42.7% w/w solution of isopropenylbenzene in acetone. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Answer:
The answer to the question is as follows
The mass of solution the student should use is 23.42 g.
Explanation:
To solve the question we note the following
A solution containing 42.7 % w/w of isopropenylbenzene in acetone has 42.7 g of isopropenylbenzene in 100 grams of the solution
Therefore we have 10 g of isopropenylbenzene contained in
100 g * 10 g/ 42.7 g = 23.42 g of solution
Available solution = 120 g
Therefore the quantity to used from the available solution = 23.42 g of the isopropenylbenzene in acetone solution.
