To easier digest this question, we can multiply the 120 servings by 4 ounces to make it into a common unit of measurement. This way, we can compare ounces with ounces instead of ounces to servings.
We then have 480 servings, and the poor caterer only has 60 ounces. We can put that into a fraction, 60/480. From here, things get slightly easier. All we have to do is make it into a fraction we can digest, which would be 1/8. We can turn that fraction into a decimal by simply dividing. We have 0.125.
Since we are changing from a decimal into a percent, we have to move the decimal point two places to the right. We have out final answer of 12.5%.
Answer:
Vertex - (2,1)
minimum
Step-by-step explanation:
minimum y≥1
Answer:
Step-by-step explanation:
x = cost of drink
y = total cost
First information: "one large pizza and 3 medium drinks cost $21.96":
3a + b = 21.96
Second information: "one large pizza and 6 medium drinks cost $30.93":
6a + b = 30.93
{3a + b = 21.96
{6a + b = 30.93
{- 3a - b = - 21.96
{6a + b = 30.93
3a = 8.97
a = 2.99
3a + b = 21.96
3•2.99 + b = 21.96
8.97 + b = 21.96
b = 21.96 - 8.97
b = 12.99
Each drink costs $2.99 and each pizza costs $12.99. The linear function rule is:
y = 2.99x + 12.99
I hope I've helped you.
Answer:
False
Step-by-step explanation:
Let p1 be the population proportion for the first population
and p2 be the population proportion for the second population
Then
p1 = p2
p1 ≠ p2
Test statistic can be found usin the equation:
where
- p1 is the sample population proportion for the first population
- p2 is the sample population proportion for the second population
- p is the pool proportion of p1 and p2
- n1 is the sample size of the first population
- n2 is the sample size of the second population.
As |p1-p2| gets smaller, the value of the <em>test statistic</em> gets smaller. Thus the probability of its being extreme gets smaller. This means its p-value gets higher.
As the<em> p-value</em> gets higher, the null hypothesis is less likely be rejected.
Factor r 4 t 4 out of 5 r 8 t 5 − 3 r 4 t 4 . r 4 t 4 ( 5 r 4 t − 3 )
