Answer:
2.4 litters of water are required.
Explanation:
Given data:
Mass of LiF = 19.6 g
Molarity of solution = 0.320 M
Volume of water used = ?
Solution:
Number of moles = mass/molar mass
Number of moles = 19.6 g/ 26 g/mol
Number of moles = 0.75 mol
Volume required:
Molarity = number of moles/ volume in L
Now we will put the values in above given formula.
0.320 M = 0.75 mol / volume in L
Volume in L = 0.75 mol /0.320 M
M = mol/L
Volume in L = 2.4 L
Answer:
The answer to your question is 8.2 g of TiF₄
Explanation:
Data
Theoretical yield = ?
mass of Ti = 5 g
mass of F₂ = 5 g
Balanced chemical reaction
Ti(s) + 2F₂ (g) ⇒ TiF₄(g)
Process
1.- Calculate the Molar mass of reactants and products
Ti = 48 g
2F₂ = 2( 19 x 2) = 76 g
TiF₄ = 48 + 76 = 124 g
2.- Calculate the limiting reactant
theoretical proportion Ti/F₂ = 48/76 = 0.63
experimental proportion Ti/F₂ = 5/5 = 1
Conclusion The limiting reactant is F₂ because the experimental proportion was lower than the theoretical proportion.
3.- Calculate the theoretical yield using the mass of F₂
76 g of F₂ --------------- 124 g of TiF₄
5 g of F₂ --------------- x
x = (5 x 124) / 76
x = 8.15 g of TiF₄
<span>A) This solution was not basic when it was heated in part 3. ( in part 3 i convertedCu(OH)2 to CuO).
Incorrectly low, because not all copper compounds will precipitate out
B) A slightly blue solution was decanted from Cu in part V. (in part 5 i reduced Cu(H20)6 ions with zink)
Incorrectly low, because some copper were thrown away
C) In part 5 the water in the beaker boiled away, exposing the evaporating dish to excess heat (same as above).
incorrectly high, because other compounds might be present as well </span>
Answer:
I can provide a proper answer since there are no choices provided.
Explanation:
